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nonlinear curve fitting: how to add an extra data vector?

2 vues (au cours des 30 derniers jours)
Ramirez
Ramirez le 24 Sep 2014
Commenté : Matt J le 25 Sep 2014
Hi, I know how to fit a curve to the ' ydata ' vector, e.g.:
opt = fitoptions('Method','NonlinearLeastSquares',...
'Startpoint',[1,0.2]);
fun = fittype('p1*cos(x)+p2*sin(x)','options',opt);
[fitobject,gof,output] = fit(time',ydata,fun)
However, I would like to include an additional data vector [same size as time and ydata(time) ] as a non-free time varying parameter [ pdata(time) ] to the function, so that we have something along this form:
fun = fittype('pdata*(p1*cos(x)+p2*sin(x))','options',opt);
Does anyone know how to implement this?

Réponses (1)

Matt J
Matt J le 24 Sep 2014
Modifié(e) : Matt J le 24 Sep 2014
You can specify the model as an anonymous function and pass parameters to that in the usual way and/or you could use the 'problem' input option to fittype/fit, see
  2 commentaires
Ramirez
Ramirez le 24 Sep 2014
I tried your suggestion using:
fun = fittype( @(p1,p2,pdata,x) pdata*(p1*cos(x)+p2*sin(x)))
[fitobject,gof,output] = fit(time',y,fun,'problem','pdata')
where pdata is a vector with the same length as y and time. However I get the following error message:
Error using fit>iAssertNumProblemParameters (line 1115) Wrong number of values for problem parameters. Specify the values as a cell array with one element for each problem parameter in the fittype.
Matt J
Matt J le 25 Sep 2014
fun = fittype( @(p1,p2,x) pdata.*(p1.*cos(x)+p2.*sin(x)),'problem','pdata');
[fitobject,gof,output] = fit(time',y,fun,'problem',pdata)

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