How can I subtract columns for each row by using a for loop
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Hi,
I have a matrix like this:
[1.011 1.004 1.054
1.008 0.998 1.042
0.984 0.988 1.024
1.026 1.006 1.016
1.000 0.996 0.977]
I would like to subtract each column for each row and store these results in a new matrix. How can I do this?
Thanks!
2 commentaires
Joseph Cheng
le 29 Sep 2014
can you expand on what you mean by subtract each column for each row? I do not understand what you're subtracting with.
Jimmy
le 29 Sep 2014
Réponse acceptée
Plus de réponses (3)
Joseph Cheng
le 29 Sep 2014
Modifié(e) : Joseph Cheng
le 29 Sep 2014
you can use combnk() or nchoosek to determine the combination of column subtraction and perform a for loop for each combination.
X = randi(10,4,3);
combin = combnk(1:size(X,2),2);
for ind = 1:size(X,2)
newX(:,ind) = X(:,combin(ind,1))-X(:,combin(ind,2));
end
Guillaume
le 29 Sep 2014
Use nchoosek to get all possible combinations of columns, and use that to calculate your differences:
m = [1.011 1.004 1.054
1.008 0.998 1.042
0.984 0.988 1.024
1.026 1.006 1.016
1.000 0.996 0.977];
colcomb = nchoosek(1:size(m, 2), 2);
coldiff = zeros(size(m, 1), size(colcomb, 1));
for comb = 1:size(colcomb, 1)
coldiff(:, comb) = diff(m(:, colcomb(comb, :)), 1, 2);
end
7 commentaires
Jimmy
le 29 Sep 2014
Guillaume
le 29 Sep 2014
Not in a matrix obviously, since it can only contain numbers. You could create a cell array of column names
colnames = cell(size(colcomb, 1));
for comb = 1:size(colcomb, 1)
colnames{comb} = sprintf('%d-%d', colcomb(comb, 2), colcomb(comb, 1));
end
Note that the difference calculated are 2-1, 3-1, 3-2, and I've represented that in the names.
Jimmy
le 29 Sep 2014
dpb
le 29 Sep 2014
For what working definition of small? But, basic idea is one of two choices...
a) go ahead and generate all pairs and then compute the comparison statistic and choose the N smallest of those, or,
b) compute each pair and the statistic at same time; after N replace the largest of those kept with the last if new is less; update the maxValue comparison value.
Jimmy
le 30 Sep 2014
Andrei Bobrov
le 30 Sep 2014
Modifié(e) : Andrei Bobrov
le 30 Sep 2014
X = [1.011 1.004 1.054
1.008 0.998 1.042
0.984 0.988 1.024
1.026 1.006 1.016
1.000 0.996 0.977];
n = nchoosek(1:size(X,2),2);
out = squeeze(diff(reshape(X(:,n'),[],2,3),1,2));
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