I have an invalid use of operator error

function [T p rho] = atmos(h)
h1 = 17; % Height of tropopause
h2 = 20; % End height of table
g = 9.81;
R = 287;
c = 6.51e-3; % temperature lapse dt/dh = - c = -6.51 degcelcius/km
T0 = 30+273.15; % Temperature sea level
p0 = 101325; % pressure sealevel
rho0 = 101325/R/T0; % density sealevel = pressure / R*T, R=287, T = 30 degcelcius
T1 = T0 - c*h1*1000; % Temperature at 17km
p1 = p0 * (T1/T0)^5.2506; % Pressure at 17km
rho1 = rho0 * (T1/T0)^4.2506; % Density at 17km
T2 = T1; % Temperature at 20km
p2 = p1 * exp(-g/(R*T2)*(h2-h1)*1000); % Pressure at 20km
rho2 = rho1 * exp(-g/(R*T2)*(h2-h1)*1000); % Density at 20km
if h <= h1
disp('Troposphere');
T = T0 - c*h*1000;
p = p0 * (T/T0)^5.2506;
rho = rho0 * (T/T0)^4.2506;
elseif h <= h2
disp('Tropopause');
T = T1;
p = p1 * exp(-g/(R*T)*(h-h1)*1000);
rho = rho1 * exp(-g/(R*T)*(h-h1)*1000);
end
h = 0:0.2:20;
for i=1:size(h,2)
[T(i), p(i), rho(i)] = atmos(h(i));
end
figure;
plot(T-273.15, h);
xlabel('Temperature (^{o}C)');
ylabel('Altitude (km)');
grid on;
figure;
plot (p,h);
xlabel('Pressure (N/m^2)');
ylabel('Altitude (km)');
grid on;
figure;
plot (rho,h);
xlabel('Density (kg/m^3)');
ylabel('Altitude (km)');
grid on;
end
I dont know what went wrong but there is a problem with the if h <= h1 part

2 commentaires

KSSV
KSSV le 19 Oct 2021
What wrong you have? Does it throw any error? It is running fine in my pc.
I fail to reproduce the problem with if h <= h1 . How did you call atmos() ?
However, I get
>> atmos(12)
...
Troposphere
Troposphere
Out of memory. The likely cause is an infinite recursion within
the program.
Error in atmos (line 34)
[T(i), p(i), rho(i)] = atmos(h(i));

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 Réponse acceptée

I have modified your function to avoid the recursive call of the function.
atmos
ans = 101×1
303.1500 301.8480 300.5460 299.2440 297.9420 296.6400 295.3380 294.0360 292.7340 291.4320
function [T,p,rho] = atmos()
h = 0:0.2:20;
len = size(h,2);
T = nan(len,1);
p = nan(len,1);
rho = nan(len,1);
for i=1:len
[T(i), p(i), rho(i)] = atmos_(h(i));
end
figure;
plot(T-273.15, h);
xlabel('Temperature (^{o}C)');
ylabel('Altitude (km)');
grid on;
figure;
plot (p,h);
xlabel('Pressure (N/m^2)');
ylabel('Altitude (km)');
grid on;
figure;
plot (rho,h);
xlabel('Density (kg/m^3)');
ylabel('Altitude (km)');
grid on;
end
function [T,p,rho] = atmos_(h)
h1 = 17; % Height of tropopause
h2 = 20; % End height of table
g = 9.81;
R = 287;
c = 6.51e-3; % temperature lapse dt/dh = - c = -6.51 degcelcius/km
T0 = 30+273.15; % Temperature sea level
p0 = 101325; % pressure sealevel
rho0 = 101325/R/T0; % density sealevel = pressure / R*T, R=287, T = 30 degcelcius
T1 = T0 - c*h1*1000; % Temperature at 17km
p1 = p0 * (T1/T0)^5.2506; % Pressure at 17km
rho1 = rho0 * (T1/T0)^4.2506; % Density at 17km
T2 = T1; % Temperature at 20km
p2 = p1 * exp(-g/(R*T2)*(h2-h1)*1000); %#ok<NASGU> % Pressure at 20km
rho2 = rho1 * exp(-g/(R*T2)*(h2-h1)*1000); %#ok<NASGU> % Density at 20km
if h <= h1
% disp('Troposphere');
T = T0 - c*h*1000;
p = p0 * (T/T0)^5.2506;
rho = rho0 * (T/T0)^4.2506;
elseif h <= h2
% disp('Tropopause');
T = T1;
p = p1 * exp(-g/(R*T)*(h-h1)*1000);
rho = rho1 * exp(-g/(R*T)*(h-h1)*1000);
end
end

4 commentaires

Hello, thank you for your help. I'm a bit new to this so can I ask what this part means?
len = size(h,2);
T = nan(len,1);
p = nan(len,1);
rho = nan(len,1);
Walter Roberson
Walter Roberson le 19 Oct 2021
size(h,2) is the number of columns in the variable h. You then store the number of columns into the variable named len
nan(len,1) means to created an array of Not A Value entries that has len rows and 1 columns. len was defined as the number of columns in h, so the result will be an array that has as many rows as h had columns, and each entry has the value NaN (Not A Number)
per isakson
per isakson le 19 Oct 2021
Modifié(e) : per isakson le 19 Oct 2021
These lines allocates memory for the vectors, T, p and rho. With large arrays it's important for performance. I use nan, because if nan is not over-written in the loop this mostly becomes obvious. See Preallocation.
Rachel Ong
Rachel Ong le 19 Oct 2021
I see, thank you for your help! :-)

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