how to find maximum value in d matrix of size (11*11)

we have a matrix of size 11*11. can u please send me the matlab code to find maximum value in the matrix as soon as possible.

Answer 1

[Yi]

If the Matrix is X; then maximum value should be max(max(X)).

for d-dimension Matrix;

s=size(X);

MaximumValue=max(X);

for i=1:(length(s)-1)

MaximumValue=max(MaximumValue);

end;

[Image Analyst]

No one familiar with MATLAB would have chosen this answer. First of all you wouldn't use a for loop when you can just use max() one time like I showed:

[maxValue, linIndexOfMax] = max(M(:))

Secondly s = [11,11] so length(s)-1 = 2-1 = 1, so the for loop just executes one time so there was no need for a loop even if you did have to call max again (which you don't). Even for a d-dimension array this loop is unnecessary - my code works for any dimension. I'd advice you not to use this answer's method. Though it works, most of the code is unnecessary and could have been done much more simply as

MaximumValue=max(X(:));

(which is what my code does) and get rid of all other lines of code.

Answer 2

[Image Analyst]

Not sure what "find" means - the value or the location - so I'll find both for you

[maxValue, linIndexOfMax] = max(M(:))
[row, column] = ind2sub(size(M), linIndexOfMax);

For example

M = magic(3)
[maxValue, linIndexOfMax] = max(M(:))
[row, column] = ind2sub(size(M), linIndexOfMax)

In the command window:

M =
     8     1     6
     3     5     7
     4     9     2
maxValue =
     9
linIndexOfMax =
     6
row =
     3
column =
     2

[Yi]

WOW, that's what I did not know. Thank you for the correction .

[Image Analyst]

Here's another quirk that trips people up all the time - it's about the size function as applied to images: http://blogs.mathworks.com/steve/2011/03/22/too-much-information-about-the-size-function/