how to find maximum value in d matrix of size (11*11)
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we have a matrix of size 11*11. can u please send me the matlab code to find maximum value in the matrix as soon as possible.
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Yi
le 5 Oct 2014
Modifié(e) : Yi
le 5 Oct 2014
If the Matrix is X; then maximum value should be max(max(X)).
for d-dimension Matrix;
s=size(X);
MaximumValue=max(X);
for i=1:(length(s)-1)
MaximumValue=max(MaximumValue);
end;
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Image Analyst
le 5 Oct 2014
No one familiar with MATLAB would have chosen this answer. First of all you wouldn't use a for loop when you can just use max() one time like I showed:
[maxValue, linIndexOfMax] = max(M(:))
Secondly s = [11,11] so length(s)-1 = 2-1 = 1, so the for loop just executes one time so there was no need for a loop even if you did have to call max again (which you don't). Even for a d-dimension array this loop is unnecessary - my code works for any dimension. I'd advice you not to use this answer's method. Though it works, most of the code is unnecessary and could have been done much more simply as
MaximumValue=max(X(:));
(which is what my code does) and get rid of all other lines of code.
Plus de réponses (1)
Image Analyst
le 5 Oct 2014
Not sure what "find" means - the value or the location - so I'll find both for you
[maxValue, linIndexOfMax] = max(M(:))
[row, column] = ind2sub(size(M), linIndexOfMax);
For example
M = magic(3)
[maxValue, linIndexOfMax] = max(M(:))
[row, column] = ind2sub(size(M), linIndexOfMax)
In the command window:
M =
8 1 6
3 5 7
4 9 2
maxValue =
9
linIndexOfMax =
6
row =
3
column =
2
2 commentaires
Image Analyst
le 6 Oct 2014
Here's another quirk that trips people up all the time - it's about the size function as applied to images: http://blogs.mathworks.com/steve/2011/03/22/too-much-information-about-the-size-function/
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