stuck again with regular expression

Hey Guys, I want to get the Letter before the word CAMERA out of this String:

SHOT -31045 J CAMERA

I know i need to use regexp. I have create this code

regexp(str,'(SHOT)+\b+[0-9]+\b+(.*?)+\b(CAMERA)')

But It doesnt work. Can u help me ?

SHOT and CAMERA will always be the same. Only the NUMBER and the Letter before CAMERA can be different.

Answer 1

[Azzi Abdelmalek]

str='SHOT -31045 J CAMERA'
out=regexp(str,'\S\s+(CAMERA)','match')
out=out{1}(1)

%or if there are many cases

str='SHOT -31045 J CAMERA k  CAMERA'
out=regexp(str,'\S\s+(CAMERA)','match')
out=cellfun(@(x) x(1),out,'un',0)

[Max Müller]

Thanks and i Guess i understand what u did there. This code searches for the backspace or empty space before Camera und gives back the Word Camera + the Letter before the backspace/empty space ?

[Azzi Abdelmalek]

Or

str='SHOT -31045 J CAMERA k CAMERA'
out=regexp(str,'\S(?=\sCAMERA)','match')

Answer 2

[Guillaume]

Where did you get that regular expression from? It doesn't mean much with matlab's regexp engine (particularly the \b does not mean blank but backspace).

If you just want a single letter before CAMERA, you can just ignore everything before and the regular expression is just a letter ([A-Za-z] or just [A-Z] if just capital letters), plus at least one blank (\s+) plus camera:

s = 'SHOT -31045 J CAMERA';
letter = regexp(s, '([A-Za-z])\s+CAMERA', 'tokens', 'once')