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display 4 consecutive numbers in array

2 vues (au cours des 30 derniers jours)
Kole
Kole le 8 Oct 2014
Modifié(e) : Kole le 8 Oct 2014
I have the Array a= 9 10 11 12 17 18 19 20 23 24 How can i get the code to display when the 4 indices are consecutive and when they appear. example: 9 10 11 12 and 17 18 19 20

Réponse acceptée

Guillaume
Guillaume le 8 Oct 2014
Strangely enough, strfind also find patterns in numeric arrays:
a = [9 10 11 12 17 18 19 20 23 24];
indices = strfind(diff(a), [1 1 1])
See also Loren's blog on the subject of finding patterns for alternative algorithms.
  1 commentaire
Stephen23
Stephen23 le 8 Oct 2014
Very tidy solution.

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Plus de réponses (1)

David Sanchez
David Sanchez le 8 Oct 2014
a= [9 10 11 12 17 18 19 20 23 24];
for k=1:(length(a)-3) % k=2
if a(k:k+3)==(a(k):a(k)+3)
fprintf('repeition in position %g: \n',k);
disp(a(k:k+3));
end
end
  2 commentaires
Kole
Kole le 8 Oct 2014
Error using == Matrix dimensions must agree.
Error in hw3 (line 7) if a(i:i+3)==(a(i):(a(i)+3))
Kole
Kole le 8 Oct 2014
Modifié(e) : Kole le 8 Oct 2014
this is what i was going for but couldnt get it to work

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