how can i obtain this?

HI

ihave data with dimension 153*1 and i want to perform for loop in order to obtain 153*71 where 71 is position along horiziontal axis but i tried to perform it and i got 153*71 but duplicated rows and columns and this is doesnt make sense so how is it linspace function useful for this?

[DGM]

You haven't described what is actually being done. You have 153x1 data that you want turned into 153x71 data, but not by column replication. If not by column replication, what are the other columns supposed to be? Are they linearly increasing? Decreasing? Something else?

In other words:

x = 1:71;
y = % 153x1 column vector
z = % 153x71 array representing some undescribed function of x and y

[RADWAN A F ZEYADI]

i have obtained from % d_pred = reshape(d_pred(:,1,:),[],1,1);%convert data from 3d to column vector

[RADWAN A F ZEYADI]

it was 51 71 3

Answer 1

[Cris LaPierre]

You have not shared your code so it's a little challenging to say what is happening, but if I were to start with a 51x71x3 matrix, and wanted to change it to 153x71, where each column is all the data in the indicated column across all 'sheets', I'd use permute then reshape.

d_pred = rand(51,71,3);
D_pred = permute(d_pred,[1 3 2]);
D_Pred = reshape(D_pred,153,[]);
size(D_Pred)

ans = 1×2

153 71

Answer 2

[DGM]

I'm assuming that you want all 71 columns to be extracted in the same fashion. Consider the example:

% 5x5x3 array
A = cat(3,reshape(1:25,5,5),reshape(101:125,5,5),reshape(201:225,5,5))

A = 
A(:,:,1) =

     1     6    11    16    21
     2     7    12    17    22
     3     8    13    18    23
     4     9    14    19    24
     5    10    15    20    25


A(:,:,2) =

   101   106   111   116   121
   102   107   112   117   122
   103   108   113   118   123
   104   109   114   119   124
   105   110   115   120   125


A(:,:,3) =

   201   206   211   216   221
   202   207   212   217   222
   203   208   213   218   223
   204   209   214   219   224
   205   210   215   220   225

B = reshape(permute(A,[1 3 2]),[],size(A,2),1) % 15x5 array

B = 15×5

1 6 11 16 21 2 7 12 17 22 3 8 13 18 23 4 9 14 19 24 5 10 15 20 25 101 106 111 116 121 102 107 112 117 122 103 108 113 118 123 104 109 114 119 124 105 110 115 120 125