Question about a:h:b

I have a quick question:

if a=1, h=1, b=5, then a:h:b will turn out to be [1 2 3 4 5]

However, if I want to do backward: b:h:a

it turns out to be a 1*0 empty row vector

is there any possibility we can still equally distribute the space and make b:h:a turns out to be [5 4 3 2 1]?

Answer 1

[KSSV]

 a=1;
 h=1;
 b=5 ;
 l = a:h:b

l = 1×5

1 2 3 4 5

 m = b:-h:a

m = 1×5

5 4 3 2 1

[Lingbai Ren]

Thanks!