Effacer les filtres
Effacer les filtres

sum of series with vectors

2 vues (au cours des 30 derniers jours)
Eemil Sakki
Eemil Sakki le 15 Nov 2021
Modifié(e) : Chunru le 15 Nov 2021
Hi,
I'm trying to solve power evolution using this equation:
I have all the values but can't get the summations to work. Thanks in advance!
Rhoo = 300e-5;
Caplambda = 1e-4;
Beta = [24 123 117 262 108 45];
lambda = [0.0127 0.031 0.116 0.3106 1.4006 3.876];
t = [0:1:30];
omega = [-6789970.6255578384124380944468818, -3.6511008223873248946050418708074, -1.1912661084218293186697922029422, -0.19487209040234811114948715764004, -0.068975792970862205151653629504031, -0.015127732106203404230259546907564, 0.00000038470100602825311618155332751786];

Réponses (1)

Chunru
Chunru le 15 Nov 2021
Modifié(e) : Chunru le 15 Nov 2021
Rhoo = 300e-5;
Caplambda = 1e-4;
Beta = [24 123 117 262 108 45];
lambda = [0.0127 0.031 0.116 0.3106 1.4006 3.876];
t = [0:1:30];
omega = [-6789970.6255578384124380944468818, -3.6511008223873248946050418708074, -1.1912661084218293186697922029422, -0.19487209040234811114948715764004, -0.068975792970862205151653629504031, -0.015127732106203404230259546907564, 0.00000038470100602825311618155332751786];
nn0 = zeros(size(t));
for it = 1:numel(t)
for j=1:6 % check your formular which has j=0
s1 = sum(Beta.*lambda./(omega(j)+lambda).^2);
nn0(it) = nn0(it) + exp(omega(j)*t(it))/(omega(j)*(Caplambda+s1));
end
end
nn0 = nn0/Rhoo;

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