how to do this

3 vues (au cours des 30 derniers jours)
agil
agil le 21 Oct 2014
Réponse apportée : Shrirang le 21 Oct 2014
y=6[2A-0.5sin(A)]/pi for 0<= x <= pi/2

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Réponses (2)

Mischa Kim
Mischa Kim le 21 Oct 2014
Modifié(e) : Mischa Kim le 21 Oct 2014
Agil, what is A? Is it supposed to be x? At any rate, in MATLAB language you'd use something like
x = 0:0.1:pi/2; % crates a vector of x vals
y = 6*(2*x - 0.5*sin(x))/pi % computes y as a function of x
plot(x,y)
Shrirang
Shrirang le 21 Oct 2014
Yes above answer is right but If you are looking for system implementation then u can implement in simulink as in diagram or in m script you can write as follows (same as above answer but some changes) if (x>=0) && (x<=pi/2) y = 6*(2*x - 0.5*sin(x))/pi; else y = 0; % Depends on your requirement end

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