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why does my program terminate

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Pat
Pat le 16 Sep 2011
Clôturé : MATLAB Answer Bot le 20 Août 2021
Hiwhile i run this program my programhangs on ,dont now why,can anyone help me please
Fuzzification
[nu da]=xlsread('lymphoma dataset.xls')
cl=xlsread('class.xls');
for i=1:size(da,1)
for j=2:size(da,2)
if(j<size(da,2))
% x=str2num(da{i,j});
% if(isempty(x))
% x=0;
% end
else
c=unique(da(:,end));
% for i1=1:length(c)
% if(strcmp(c{i1},da{i,j}))
% x=i1;
% end
% end
% end
data(i,j-1)=x;
end
end
data1=data;
% data=data(1:300,:);
% cl=cl(1:150,:);
% data=nu;
disp('Dataset')
disp(data)
data=knnimpute(da)
[in claq]=kmeans(data,4);
for i=1:size(da,2)
d=data(:,i);
Emin=min(d);
Emax=max(d);
d1=sort(d,'ascend');
s=size(d,1)/3;
pj1=d(1:s,:);
pj2=d(s+1:end,:);
cl=in;
cla1=cl(1:s,:);
cla2=cl(s+1:end,:);
nc=10;
de=1;
k1 = mat2cell(pj1, nc*ones(1, (s/nc)),1);
k2 = mat2cell(pj2, nc*ones(1, (size(pj2,1)/nc)),1);
Rk1=(2*1)/length(pj1);
Rk2=(2*2)/length(pj2);
%class
figure('visible','off')
h = cdfplot(cla1);
y = get(h,'YData');
f1=length(y);
y = unique(y);
h1 = cdfplot(cla2);
y1 = get(h1,'YData');
f2=length(y1);
y1 = unique(y1);
low1=y(2);
low2=y1(2);
cf1=y(2)-y(1);
cf2=y1(2)-y1(1);
Pj1=low1+((Rk1-cf1)/f1)*de;
Pj2=low2+((Rk2-cf2)/f2)*de;
Aj1(i)=(Emin+ Pj1)/2;
Aj2(i) =(Pj1 + Pj2 )/2;
Aj3(i)= (Pj2 + Emax )/2;
end
  3 commentaires
Andreas Goser
Andreas Goser le 16 Sep 2011
And also be specific about "terminate"
Jan
Jan le 18 Sep 2011
@Pat: You've asked 41 questions now. I'd expect that you've learned how to ask good questions and how to format your code. If you interested in getting answers, make your question easy to understand and to read would be a good idea.

Réponses (1)

Vineeth Kartha
Vineeth Kartha le 3 Mai 2016
Hi,
Insert breakpoints at each xlsread command and see if it is one of the xlsread that is causing the problem.
Regards Vineeth
  1 commentaire
Jan
Jan le 3 Mai 2016
@Vineeth Kartha: Did you see that the question is 5.5 years old and that the OP did not reply to questions for clarifications? I assume he was not interested in a solution.

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