Effacer les filtres
Effacer les filtres

How to apply an equation to each element in the array?

4 vues (au cours des 30 derniers jours)
KarolN
KarolN le 27 Nov 2021
Commenté : KarolN le 28 Nov 2021
I have an equation:
Which I need to apply to every element in a 10x10 matrix of u.
u - a node in numerical model of rock layer
j,n - indexes of movement
The matrix is supposed to have identical starting values of 80.

Réponse acceptée

Matt J
Matt J le 27 Nov 2021
conv( u , [0 1 0]+alpha*[1 -2 1] )
  5 commentaires
Matt J
Matt J le 28 Nov 2021
Use conv2 instead
soilSub = conv2( u, [0 1 0]+alpha*[1 -2 1] )
KarolN
KarolN le 28 Nov 2021
IT WORKS! Thank you very much for your valuable advice!

Connectez-vous pour commenter.

Plus de réponses (1)

Image Analyst
Image Analyst le 28 Nov 2021
Try conv2():
k = 10^-7 % filtration of soil
M = 19000
q = 80 % external force Q acting on soil
DeltaZ = 0.1 % depth of soil subsidization
GammaW = 10 % water weight [Kn/m^3]
Cv = k*M/GammaW % consolidation factor
DeltaT = DeltaZ^2/(2*Cv) % max iteration step
alpha = Cv*DeltaT/DeltaZ^2
% NUMERICAL PARAMETERS
u = q*ones(10:10) % matrix of u nodes
% SOLUTION
kernel = [0, 1, 0] + alpha * [1, -2, 1]
% Discrete form of the governing equation:
soilSub = conv2(u, kernel) % Use conv2(), not conv()
  4 commentaires
Image Analyst
Image Analyst le 28 Nov 2021
No problem. I'm sure using conv() instead of conv2() was just an oversight by Matt. I know he knows better - he's a bright guy. You can vote for multiple answers though you can only Accept one. You can even vote for one you Accepted to award double the reputation points to that one.
KarolN
KarolN le 28 Nov 2021
And so additionally I learned about that vote feat :) Voted for both of you naturally. Thanks guys

Connectez-vous pour commenter.

Catégories

En savoir plus sur Programming dans Help Center et File Exchange

Produits


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by