Remove value question: if previous row -row>+-3, then remove the row in matrix A

2 vues (au cours des 30 derniers jours)
Hi, I am a beginner at coding. I would like to know why did my code is not working. I have a matrix A, I would like to subtract every two rows for all my rows in the same matrix, and if the subtract >+-3, then remove the row.
A = [1;9;5;4;3;6;764;465;6;8;7;5;3;6;8;8;56;6;4;3;6;8;2;4;6;8;9;22;4]
example:
if row(2,1)-row(1,1)>(+-3) then I want to remove row(1,1) in matrix A
i try to code this:
A = [1;9;5;4;3;6;764;465;6;8;7;5;3;6;8;8;56;6;4;3;6;8;2;4;6;8;9;22;4]
for j = 1:size(A)
if A(j+1,1)-A(j,1)>+-3
A(j,1)=[]
end
end
However, it is not working...please help me confirm the following information. I am appreciative of your help!!

Réponse acceptée

Matt J
Matt J le 5 Déc 2021
Modifié(e) : Matt J le 5 Déc 2021
A(diff(A)>-3)=[]
or
A(abs(diff(A))<3)=[];
if that's what you really meant.
  2 commentaires
tengteng QQ
tengteng QQ le 6 Déc 2021
thank you for your help!! I really appreciative it!!
Matt J
Matt J le 6 Déc 2021
You're welcome, but please Accept-click the answer if it solved your problem.

Connectez-vous pour commenter.

Plus de réponses (1)

Jan
Jan le 5 Déc 2021
Your code contains some problems:
  • for j = 1:size(A)
Remember, that size() replies a vector containing the size of all dimensions. In the expression 1:size(A) only the first element of size(A) is used. Better:
for j = 1:numel(A) % or size(A, 1)
A 2nd problem: You check A(j+1). Then j is not allowed to be numel(A), but the loop must stop one element before.
  • if A(j+1,1)-A(j,1)>+-3
The expression "+-" is not defined in Matlab. I assume you want:
if abs(A(j+1,1) - A(j,1)) > 3
  • A(j,1)=[]
After you have deleted one element, the original array is shorter. Then the loop must fail, because elements after the last one are tested.
I assume you want:
A = [1;9;5;4;3;6;764;465;6;8;7;5;3;6;8;8;56;6;4;3;6;8;2;4;6;8;9;22;4]
delete = false(size(A));
for j = 1:numel(A) - 1
delete(j + 1) = abs(A(j+1,1) - A(j,1)) > 3;
end
A(delete) = [];

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by