Extending the vector length

I have a signal with sampling frequency of 20000 and the total lenght of the signal is 200010. Now I want to take a paticular sample around 181600 and give a new variable but I am encountering an error (Index exceeds array bounds.). I could understand clearly that the orginal lenth is less thamn the new length.

Now how should I add zeros to the orginal vector (ch_x1_interval_1) so that it should extend with zeros to the remaining data to get the new signal.

Below is the code that I used it would be very nice to give comments to the code given below.

ch_x1_interval_1_new =ch_x1_interval_1(181600:181600+20000);

Thank you.

[VG]

I tried doing it manually by adding zeros and it worked.But its the hard way to do that.

Answer 1

[KSSV]

Two options.

Option 1:Use interpolation to extend the size.

n = length(ch_x1_interval_1) ;
x = 1:n ;
xi = linspace(1,n,181600) ;
iwant = interp1(x,ch_x1_interval_1,xi) ;

Option 2: Appending zeros

n = length(ch_x1_interval_1) ;
m = 181600 ;
iwant = zeros(1,m) ;
iwant(1:n) = ch_x1_interval_1 ;