Hi guys,
How would I write a for loop in which the loop variable runs from 0 to pi/2 in steps of 0.01?
Am i right in saying:
for
A = 0:0.01:pi/2
end
Is this correct?

 Réponse acceptée

Yusuf Suer Erdem
Yusuf Suer Erdem le 7 Déc 2021
Modifié(e) : Yusuf Suer Erdem le 7 Déc 2021
for a=0:a+0.01:pi/2
disp(a)
end

4 commentaires

Laura T
Laura T le 7 Déc 2021
Thank you! And if i were to add inside this loop do i need to disp(i) every time i enter a new line of code?
Yusuf Suer Erdem
Yusuf Suer Erdem le 7 Déc 2021
disp(i) is just to show you that the loop works. you could do anything you want with that i value.
The colon operation given in the answer uses the imaginary unit in the step, which leads to this warning:
0:i+0.01:pi/2
Warning: Colon operands must be real scalars.
ans = 1×158
0 0.0100 0.0200 0.0300 0.0400 0.0500 0.0600 0.0700 0.0800 0.0900 0.1000 0.1100 0.1200 0.1300 0.1400 0.1500 0.1600 0.1700 0.1800 0.1900 0.2000 0.2100 0.2200 0.2300 0.2400 0.2500 0.2600 0.2700 0.2800 0.2900
I don't see any reason why the step needs to use the imaginary unit.
Yusuf Suer Erdem
Yusuf Suer Erdem le 7 Déc 2021
maybe used i as a character. i changed it with a. it should be okey now.

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