Find the minimums along 3rd dimension of an array

I have a 3d array that is constructed from two 2d arrays:

a = [1 2 3; 4 5 6; 7 8 9];
b = [1 2 0; 4 0 9; 9 8 9];
c = cat(3,a,b);

I want to find the minimums along dimension 3 only.

Desired output:

c_mins =

1 2 0

4 0 6

7 8 9

I thought this would work but it seems to give a different result which I don't understant:

min(c, 3)

ans(:,:,1) =

1 2 3

3 3 3

3 3 3

ans(:,:,2) =

1 2 0

3 0 3

3 3 3

Answer 1

[Image Analyst]

You need [] in min():

a = [1 2 3; 4 5 6; 7 8 9];
b = [1 2 0; 4 0 9; 9 8 9];
c = cat(3,a,b)

c = 
c(:,:,1) =

     1     2     3
     4     5     6
     7     8     9


c(:,:,2) =

     1     2     0
     4     0     9
     9     8     9

minValues = min(c, [], 3)

minValues = 3×3

1 2 0 4 0 6 7 8 9

[Bill Tubbs]

Thanks. I should have read the docs! I thought it was like all(X,DIM).

[Image Analyst]

@Bill Tubbs, yeah, sometimes there are inconsistencies like that.

[Steven Lord]

If I recall correctly the syntax min(A, B) predates the introduction of 3-dimensional arrays into MATLAB (both of which predate the start of my tenure at MathWorks.) We don't want min(A, scalar) to be ambiguous if the scalar is a potential dimension number so we instead treat it always as B.