Unable to compare equality of two matrices
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I am trying to compare the two 4x4 matrices below and generate a success message, but I see that the code is able to display a success message only for the first element of each row. Can anyone spot where I made the mistake please?
Rotation_matrix = rotm2tform([0.9254 0.0180 0.3785; 0.1632 0.8826 -0.4410; -0.3420 0.4698 0.8138])
res = rpy2tr(30*pi/180,20*pi/180,10*pi/180)
k=0
for i = 1:size(Rotation_matrix)
for j = 1:size(res)
if isequal(i,j)
continue
else
disp("Fail")
k=1;
end
end
end
if k==0
disp("Verification success")
end
Thank you
0 commentaires
Réponses (1)
Walter Roberson
le 27 Déc 2021
size() of a variable, when no option is provided in the size() call, always returns a vector, even if the variable is a scalar. When you use 1:size() then you are using 1 colon a vector . MATLAB does define that: it takes the first element of the vector. So 1:size(Rotation_matrix) is going to be the same as 1:size(Rotation_matrix,1) which might not be what you want.
Question: why are you comparing the indices instead of comparing the matrix indexed at the indices?
You should also read http://matlab.wikia.com/wiki/FAQ#Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero.3F
0 commentaires
Voir également
Catégories
En savoir plus sur Multidimensional Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!