My implemetation for Newton's method doesn't seem to be working
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My goal is to solve the following set of nonlinear equations:
for this I use the Newton method in the form:
The code to define my equations is given by:
function Fn=f_test(x)
Fn=[x(1)^2-x(2)+x(3)^3-26;x(1)+x(2)+x(3)-6;x(1)^2+x(2)^3-x(3)^2];
The code to compute the Jacobian is given by:
function [J]=mat_jac(x,f)
% computes the Jacobian of a function
n=length(x);
eps=1e-5; % could be made better
J = zeros(n,n);
T=zeros(1,n);
for i=1:n
T(i)=1;
x_plus = x+eps*T;
x_minus = x-eps*T;
J(:,i) = (f_test(x_plus)-f_test(x_minus))/(2*eps);
T(i)=0;
end
My test script is given by:
%This tests the algorithm
x=[0.5 0.5 0.5];
x_old=x';
end_error=1e-5;
error=10;
while (error>end_error)
J=mat_jac(x_old',f_test(x_old'));
F=-f_test(x_old);
dx=linsolve(J,F);
x_new=x_old+dx;
x_old=x_new;
error=norm(f_test(x_old));
end
The solution to these equations is x=1,y=2,z=3 and I'm starting the search off at x=0.5,y=0.5,z=0.5. I know my jacobian is correct as I've checked it and my Newton's method looks correct so I don't know where I'm going wrong. Any suggestions?
2 commentaires
Jan
le 6 Jan 2022
You forgot to mention, what the problem is. Why do you assume that there is something wrong?
Réponse acceptée
Jan
le 11 Jan 2022
I've cleanup the code, e.g. removed the not needed "x_old". Avoid using the names of important Matlab functions as variables: eps, error. Avoid mixing row and column vectors frequently, but just work with column vectors in general.
Finally, it does converge.
x = [0.5; 0.5; 0.5];
limit = 1e-5;
err = 10;
loop = 0;
while err > limit
J = mat_jac(x, @f_test); % 2nd argument is not f_test(x)
F = f_test(x);
x = x - J \ F;
err = norm(f_test(x))
loop = loop + 1;
if loop == 1e5
error('Does not converge!');
end
end
function J = mat_jac(x, f)
n = length(x);
v = 1e-8;
J = zeros(n, n);
T = zeros(n, 1);
for i=1:n
T(i) = 1;
J(:, i) = (f(x + v * T) - f(x - v * T)) / (2 * v);
T(i) = 0;
end
end
function Fn = f_test(x)
Fn = [x(1)^2 - x(2) + x(3)^3 - 26; ...
x(1) + x(2) + x(3) - 6; ...
x(1)^2 + x(2)^3 - x(3)^2];
end
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