Variable change at every time step
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RAKESH KUMAR TOTA
le 11 Jan 2022
Commenté : RAKESH KUMAR TOTA
le 11 Jan 2022
for i = 1 :1000
a(:,i) = b ;% assume b size 800 X 1 vector
% but b size changes at random iteration (for loop) depends on the problem i mean it size
% decrease so how to store b values in a as it showing error
end
Error:
Unable to perform assignment because the size of the left side is 1-by-800 and
the size of the right side is 797-by-1.
Other case :
for i = 1 :1000
a(:,i) = b'; % assume b size 800 X 1 vector
% but b size changes at random iteration (for loop) depends on the problem i mean it size
% decrease so how to store b values in a as it showing error
end
Unable to perform assignment because the indices on the left side are not
compatible with the size of the right side.
I can understand what error showing but how to tackle this problem. Any help appreciated .
Thanks in advance.
4 commentaires
VBBV
le 11 Jan 2022
Can you paste the actual error that you faced. Everything in red color text shown at command window
Réponse acceptée
KSSV
le 11 Jan 2022
When you are not sure of size b, you can save them into a cell array.
a = cell(1000,1) ;
for i = 1 :1000
a{i} = b ;
end
You can access any cell using a{1}, a{2},....a{i},...a{1000}.
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