How to reshape an array into 3 different matrix with different sizes?

2 vues (au cours des 30 derniers jours)
Hana
Hana le 19 Nov 2014
Modifié(e) : Matt J le 19 Nov 2014
I want to reshape A into 3 matrices m1,m2,m3:
A=[1 2 3 4 5 6 7 8 9 4 5 3 5 3 2 5 4 2 4 7 5 ];
m1=-9999*ones(3,3);
m2=-9999*ones(2,2);
m3=-9999*ones(2,4);
the result should look like:
m1=[1 2 3 ;4 5 6 ;7 8 9];
m2=[4 5 ;3 5];
m3=[3 2 5 4; 2 4 7 5];
  1 commentaire
David Young
David Young le 19 Nov 2014
"Reshape" normally means to change the shape but keep the same number of elements. Here, though, all the matrices have different numbers of elements. Please could you define the operation you need more exactly?

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Shane
Shane le 19 Nov 2014
It looks like you just want to split the array up.
A=[1 2 3 4 5 6 7 8 9 4 5 3 5 3 2 5 4 2 4 7 5 ];
subData1 = A(1:9);
subData1 = reshape(subData1, [3 3]);
subData2 = A(10:13);
subData2 = reshape(dubData2, [2 2]);
subData3 = A(14:21);
subData3 = reshape(subData3, [ 4 4]);
This is all manually mind you. If your data structure will change dynamically you will want to try something different.

Plus de réponses (1)

Matt J
Matt J le 19 Nov 2014
Modifié(e) : Matt J le 19 Nov 2014
After the lines you've shown with m123=-9999*ones(...) do the following
m1(:)=A(1:9);
m2(:)=A(10:13);
m3(:)=A(14:end);
and transpose as needed.

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