Hello friends!
Consider a binomial symbolic expression like (x-1)^3 and a symbolic vector e of size 3 (e=sym('e',[1 3]) ). Of
course, in my real problem I have 'n' instead of 3 but I just used 3 here for simplicity. If expand (x-1)^3 then I get
(x-1)^3 = x^3-3*x^3+3*x-1;
which includes all powers of x from 0 to 3, as we know. Now, I need to substitute x with e(1), x^2 with e(2), x^3 with e(3).
Unfortunately, I cannot use 'subs' command here since when I try to assign x with e(1), it automatically assigns x^2 with
e(1)^2 and x^3 with e(1)^3 which is not what I want (similarly, if I try to asign x^2 with e(2) it might interfere with other powers
of x).
Ant idea?
Thanks!
Babak

2 commentaires

Rik
Rik le 26 Jan 2022
If by e(k) you mean exp(k), isn't the replacement equivalent to what you want? It might not look tidy, but it is the same number.
Mohammad Shojaei Arani
Mohammad Shojaei Arani le 27 Jan 2022
No. I do not mean exp. 'e' is just a symbolic array. If you look at the title of mt post "Replace powers with asequence" you will see that I am not cconsidering a specific sequence.

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Réponses (1)

Torsten
Torsten le 26 Jan 2022

0 votes

syms x
c = sym2poly(expand((x-1)^3));
e = sym('e',[3,1]);
c_times_e = c*e

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