How to arrange a column vector into two columns?

So, I have this vector and I need to arrange it as loops. Each value for each loop should start as the next integer from the previous ending loop x= [128 147 166 181 195 216 236 255]

It should look something like this x= [128 147; 148 166; 167 181; 182 195; 196 216; 217 236; 237 255]

I cannot do it manually, since I have to arrange several vectors that will not have the same length as this one. I tried using nested for loops but wasn't successful

[Stephen23]

@David Silva: why do you ignore the second-to-last value (236) when creating the output matrix?

[KSSV]

May be becuase, it falls in the intervel [217 255].

[Stephen23]

"May be becuase, it falls in the intervel [217 255]."

Every (non-end) element in that vector falls in the interval formed by its adjacent elements. What is so special about 236?

[Heirleking]

You are right, I corrected the mistake

Answer 1

[Stephen23]

Assuming that the missing 236/237 row is a mistake:

x = [128,147,166,181,195,216,236,255]

x = 1×8

128 147 166 181 195 216 236 255

m = [x(1),1+x(2:end-1);x(2:end)].'

m = 7×2

128 147 148 166 167 181 182 195 196 216 217 236 237 255