How can I stored the for loop data ...for each loop..Its overwriting the previous data .. I am storing in C..But it is taking only last loop by overwriting previous values any inputs how can I do this ...Thank you in Adance ...any improvement in code can someone suggest
clear all
close all
clc
A=xlsread('Compare_All_cases','B1:AB37');
B=[]
for i= 1:12
B=[B;A(i,:)]
end
for i=1:3:12
effi1=(B(i,:)-B((i+1),:))./(B(i,:))*100
effi2=(B((i+1),:)-B((i+2),:))./(B((i+1),:))*100
effi3=(B(i,:)-B((i+2),:))./(B(i,:))*100
C=vertcat(effi1,effi2,effi3);
end

 Réponse acceptée

KSSV
KSSV le 9 Fév 2022
Modifié(e) : KSSV le 9 Fév 2022

1 vote

The below line
A=xlsread('Compare_All_cases','B1:AB37');
B=[]
for i= 1:12
B=[B;A(i,:)]
end
can be achieved by:
A=xlsread('Compare_All_cases','B1:AB37');
A = A' ;
B = A(:) ;
The rest of the lines:
for i=1:3:12
effi1=(B(i,:)-B((i+1),:))./(B(i,:))*100
effi2=(B((i+1),:)-B((i+2),:))./(B((i+1),:))*100
effi3=(B(i,:)-B((i+2),:))./(B(i,:))*100
C=vertcat(effi1,effi2,effi3);
end
can be used:
C = cell([],1) ;
count = 0;
for i=1:3:12
count = count+1 ;
effi1=(B(i,:)-B((i+1),:))./(B(i,:))*100
effi2=(B((i+1),:)-B((i+2),:))./(B((i+1),:))*100
effi3=(B(i,:)-B((i+2),:))./(B(i,:))*100
C{i}=vertcat(effi1,effi2,effi3);
end
You can convert the above cell into a amtrix. Read about Cell2mat.

4 commentaires

Prasad Joshi
Prasad Joshi le 9 Fév 2022
Thank you sir
KSSV
KSSV le 9 Fév 2022
Or if the size of C is same.
C = zeros([],3) ;
count = 0;
for i=1:3:12
count = count+1 ;
effi1=(B(i,:)-B((i+1),:))./(B(i,:))*100
effi2=(B((i+1),:)-B((i+2),:))./(B((i+1),:))*100
effi3=(B(i,:)-B((i+2),:))./(B(i,:))*100
C(i,:) = [effi1,effi2,effi3];
end
Prasad Joshi
Prasad Joshi le 9 Fév 2022
Thank you sir ...for more information ...
Prasad Joshi
Prasad Joshi le 9 Fév 2022
Can you answer this also sir if possible ...if you give hint for that variable / syntax that would also be fine .. thank you in advance sir ..

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