is my script having 51 equally spaced points?

    clc;clear all;
    l=25;E=200e9;I=350e-6;w=6e3;
    x1=linspace(0,l/2,25)
    for n = 1 : length(x1)
        y1(n)=(-(w*x1(n))/(384*E*I))*(16*(x1(n)^3)-24*l*(x1(n)^2)+9*(l^3))
    end
        x2=linspace(l/2,l,26)
    for n = 1 : length(x2)
        y2(n)=(-(w*x2(n))/(384*E*I))*(8*(x2(n)^3)-24*l*(x2(n)^2) ...
               +17*x2(n)*(l^2)-(l^3) )
    end
    x = [x1, x2];
    y = [y1, y2];
    plot(x,y, '.')
    xlabel('x-axis,length(m)')
    ylabel('y-axis,deflection(m)')

[Roger Stafford]

I would say, most definitely not equally-spaced! The two functions you are plotting are quartic polynomials in which the derivatives are certainly changing over the interval plotted. Even the x values are not equally-spaced, since there are 25 values in the first half interval and 26 in the second half.

[ernest]

what do u suggest the values i should enter for x to be equally spaced with 51 points. using linspace of course

[Roger Stafford]

   x = linspace(0,L,51); % I used uppercase L instead of lowercase l
   x1 = x(1:25);
   x2 = x(26:51);
   ...

Answer 1

[Image Analyst]

If you want them equally spaced along the curve, you'll have to use interparc():

http://www.mathworks.com/matlabcentral/fileexchange/34874-interparc

If you just want uniform spacing along the x, then just use linspace on x once.

[ernest]

What do you suggest the values I should put for x to have 51 equally spaced points?

Using linspace() of course.

[ernest]

using linspace ofcourse

[Image Analyst]

Replace the x2 assignment with this:

deltaX = x1(2) - x1(1)
x2= l/2 : deltaX : 26;

Now x2 will have the same spacing as x1 and your combined [x1,x2] array has 51 elements. Another way using linspace() is to create the whole thing and extract the portions you want for x1 and x2:

x = linspace(0, 26, 51);
x1 = x(1:25);
x2 = x(26:end);

Don't forget to get rid of the x2 assignment in between the for loops if you do it this way!

[ernest]

thanks man. appreciate the help

[Image Analyst]

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