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Assigned small array values into Big array using for loops

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Ankitkumar Patel
Ankitkumar Patel le 28 Fév 2022
Commenté : Ankitkumar Patel le 28 Fév 2022
Size(per)=1*(multiple of 180) double; e.g. 1*720
Size(temp)=180*1 double
as of 720/180=4;
My goal is to assign temp values in per like these per(1:4)=temp(1); per(5:8)=temp(2), ...., per(717:720)=temp(180). How can I perfect second for loop??
for j=1:length(temp)
for i =1:length(per)/length(temp)
per(i)=temp(j);
end
end

Réponse acceptée

Stephen23
Stephen23 le 28 Fév 2022
Modifié(e) : Stephen23 le 28 Fév 2022
per = repelem(temp,4)
Or if it is required to use some indexing:
per(:) = repelem(temp,4)

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