Hi, is there any algorethim to select random points from a large data file. Lets say I want to select data after every 20 values. x = [1:0.1:1000]
If I want y = select every 10th 20th or 50th point of x
Thanks Amb

4 commentaires

per isakson
per isakson le 12 Déc 2014
Modifié(e) : per isakson le 12 Déc 2014
Try
>> M = 1:100;
M(20:20:100)
ans =
20 40 60 80 100
but that's hardly random.
Azzi Abdelmalek
Azzi Abdelmalek le 12 Déc 2014
The question is not clear, "10th 20th or 50th point of x"
amberly hadden
amberly hadden le 12 Déc 2014
Sorry if its not clear I mean to write pick every 10th or 20th point of x.
Amb
amberly hadden
amberly hadden le 12 Déc 2014
sorry random means scanig rando area up down lesft right

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 Réponse acceptée

Mohammad Abouali
Mohammad Abouali le 12 Déc 2014
x = [1:0.1:1000];
x_every10th=x(10:10:numel(x));
x_every20th=x(20:20:numel(x));
x_every50th=x(50:50:numel(x));
You get the idea.

4 commentaires

amberly hadden
amberly hadden le 12 Déc 2014
Thanks but its out put is 1*2 matix. Quit differnt from what I want
here is an example lets say x = a b c (3*2000 Matrix) I want to pick every 10th value of x means I need to output x = a10 b10 c10:a20 b20 c20 and so on for means pick every 10th value
So you are changing the question. In your question x is a row vector now it is matrix. and you want every 10th, 20th, ... row
then change it to this:
x_every10th=x(10:10:size(x,1),:);
x_every20th=x(20:20:size(x,1),:);
x_every50th=x(50:50:size(x,1),:);
amberly hadden
amberly hadden le 12 Déc 2014
yeah I have a 307000*3 matrix
want to select every 10th row. Is there any wany to data from random rows lets say for region I'm more interested I can select every 20th point for region Im not much interested slect every 50th and close to my sourse select every 10th point.
Thanks much apriciated
amberly hadden
amberly hadden le 12 Déc 2014
another thing I want out put in 3 columns its just producing one column.

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Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 12 Déc 2014
x = [1:0.1:1000];
n=randi(5)*10
out=x(n:n:end)

1 commentaire

amberly hadden
amberly hadden le 12 Déc 2014
randi is good option but how would I aviod repeation
Thanks

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