How to create this patterned matrix?

How do I create a matrix that looks like this?

Answer 1

[Stephen23]

N = 8;
M = toeplitz(0:N-1,[0,N:-1:1]);
M(N,:) = N:-1:0

M = 8×9

0 8 7 6 5 4 3 2 1 1 0 8 7 6 5 4 3 2 2 1 0 8 7 6 5 4 3 3 2 1 0 8 7 6 5 4 4 3 2 1 0 8 7 6 5 5 4 3 2 1 0 8 7 6 6 5 4 3 2 1 0 8 7 8 7 6 5 4 3 2 1 0

Answer 2

[Davide Masiello]

Generalizing for any nxn matrix

clear,clc
n = 9;
A = zeros(n);

for i = 1:n
    A(i,i+1:n) = flip(i:n-1);
    if i > 1
    A(i,1:i) = flip(0:i-1);
    end
end

which yields

A =

     0     8     7     6     5     4     3     2     1
     1     0     8     7     6     5     4     3     2
     2     1     0     8     7     6     5     4     3
     3     2     1     0     8     7     6     5     4
     4     3     2     1     0     8     7     6     5
     5     4     3     2     1     0     8     7     6
     6     5     4     3     2     1     0     8     7
     7     6     5     4     3     2     1     0     8
     8     7     6     5     4     3     2     1     0
     

However, in your example, the row starting with 7 is missing. I am not sure whether that's intentional or just a typo.

In the first instance, the code above can be arranged to remove rows starting with a certain value.

[Stephen23]

"Generalizing for any nxn matrix"

The OP requested an 8x9 matrix (which is not square).

Check the last rows of the OP's matrix too, you will find that they do not match your answer.

[Burger King]

I didnt even realize it was "5 6 8". Thanks a lot man

[Davide Masiello]

Anytime! I guess you indeed wanted that row to be skipped. @Stephen's answer will do that very efficiently.

Answer 3

[Arif Hoq]

try this:

x=[0,8,7,6,5,4,3,2,1];
A1=circshift(x,1);
A2=circshift(x,2);
A3=circshift(x,3);
A4=circshift(x,4);
A5=circshift(x,5);
A6=circshift(x,6);
A7=circshift(x,8);
Matrix=[x;A1;A2;A3;A4;A5;A6;A7]

Matrix = 8×9

0 8 7 6 5 4 3 2 1 1 0 8 7 6 5 4 3 2 2 1 0 8 7 6 5 4 3 3 2 1 0 8 7 6 5 4 4 3 2 1 0 8 7 6 5 5 4 3 2 1 0 8 7 6 6 5 4 3 2 1 0 8 7 8 7 6 5 4 3 2 1 0