As I understand, the exist() function in MATLAB will return "2" if the input is a MATLAB function.
The list of options for the second input 'kind' are builtin, class, dir, file, and var.
I want to input 'kind' so that exist() will ONLY search for functions, and return 2 if it is a match to a function and a 0 if not.
Is there any way to do this?

2 commentaires

Sean de Wolski
Sean de Wolski le 22 Déc 2014
So you mean ONLY functions or any MATLAB files that will run (scripts/functions/classes)? which will return something for scripts and classes as well.
Sean de Wolski
Sean de Wolski le 22 Déc 2014
For functions only, this blog post and ensuing comments explains:

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 Réponse acceptée

matt dash
matt dash le 19 Déc 2014

2 votes

An option that is not exactly what you describe, but might work for you:
isempty(which([functionname,'.m']))

5 commentaires

... but why not just
isempty(which( functionname ))
matt dash
matt dash le 20 Déc 2014
Without the .m it will not distinguish between functions and variables.
per isakson
per isakson le 20 Déc 2014
Modifié(e) : per isakson le 20 Déc 2014
Yes, exactly!
Daniel
Daniel le 22 Déc 2014
Will this work in a deployed application? since the file isn't actually on the filepath any longer as its packaged in an EXE?
Sean de Wolski
Sean de Wolski le 22 Déc 2014
What about p-files?

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Plus de réponses (1)

Azzi Abdelmalek
Azzi Abdelmalek le 19 Déc 2014
Modifié(e) : Azzi Abdelmalek le 19 Déc 2014

0 votes

exist()==2
%or
A = exist('name','file')

1 commentaire

Daniel
Daniel le 19 Déc 2014
My problem here is what if it exists as a workspace variable or another non-m file on the search path? in that case it will return 1 or 5 respectively, while I would still not be sure if it exists as a funciton.

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