exportgraphics dynamic file name

12 vues (au cours des 30 derniers jours)
Pelajar UM
Pelajar UM le 22 Mar 2022
Commenté : Ive J le 22 Mar 2022
What's the correct syntax if you want to name the files dynamically when using exportgraphics?
I have a cell array A with 16 titles in each columns that are assigned to the colorbar string. I want to use the same titles to name the files.
for k = 1:16
%rest of the code
c = colorbar;
c.Label.String = string (A (:,k));
exportgraphics(gcf, string (A(:,k)) '.png' ,'Resolution',DPI) %this doesn't work
end

Réponse acceptée

Ive J
Ive J le 22 Mar 2022
% A = {'name1', ...}
for k = 1:16
%rest of the code
c = colorbar;
c.Label.String = A{k};
exportgraphics(gcf, string(A{k}) + ".png" ,'Resolution',DPI) %this doesn't work
end
You could also use strcat, join or similar functions.
  10 commentaires
Pelajar UM
Pelajar UM le 22 Mar 2022
Exactly what I was looking for. Thanks a lot!
Ive J
Ive J le 22 Mar 2022
Glad it works
cheers!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Lighting, Transparency, and Shading dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by