Inserting missing dates and values

16 vues (au cours des 30 derniers jours)
Mohammad Sayeed
Mohammad Sayeed le 23 Déc 2014
Commenté : Ana Soph le 18 Mai 2020
I have two column matrix representing a time series data with daily interval. But I have few missing data so some of the dates are not shown in the matrix. But I need to insert all possible dates in the data series where the missing values should be equal to the previous day’s value. Can I do it in Matlab? For example the matrix looks like x=[Jan1 10; Jan2 12; Jan4 16] but it should be x=[Jan1 10; Jan2 12; Jan3 12; Jan4 16]. It looks very simple in this example but I have millions of data so it is not possible to correct manually. Anyone can help please?
  6 commentaires
Image Analyst
Image Analyst le 18 Mai 2020
Modifié(e) : Image Analyst le 18 Mai 2020
You said you have the same problem as Mohammad. The two answers below offered a solution so there is a chance they may work for you also. If you already read them and you say it does not apply to your problem, then evidently you do not have the same problem (kind of a contradiction). So we're now not sure if you have the same problem or not. Anyway...
If you have a different problem, read this link first, and then post your own new question with your own data attached.
Ana Soph
Ana Soph le 18 Mai 2020
i already read the link and put my answer. Have a great day

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Réponses (2)

Steven Lord
Steven Lord le 10 Nov 2017
Modifié(e) : Steven Lord le 10 Nov 2017
If you're using a release of MATLAB that includes timetable, create a timetable with your data then use retime on that timetable.
% Create some time and data variables
>> t = datetime(2017, 1, [1; 2; 4]);
>> x = [10; 12; 16];
% Assemble the timetable and display it
>> tt = timetable(t, x)
tt =
3×1 timetable
t x
___________ __
01-Jan-2017 10
02-Jan-2017 12
04-Jan-2017 16
% Generate daily data in your timetable, filling in new rows with
% the previous day's data
>> tt2 = retime(tt, 'daily', 'previous')
tt2 =
4×1 timetable
t x
___________ __
01-Jan-2017 10
02-Jan-2017 12
03-Jan-2017 12
04-Jan-2017 16
% Generate daily data in your timetable, but fill new rows with missing data
% For a double variable, 'missing' means NaN
>> tt3 = retime(tt, 'daily', 'fillwithmissing')
tt3 =
4×1 timetable
t x
___________ ___
01-Jan-2017 10
02-Jan-2017 12
03-Jan-2017 NaN
04-Jan-2017 16

Image Analyst
Image Analyst le 23 Déc 2014
I don't know what type of data x is, but convert them to a number with sprintf() and datenum(). Then use interp1() to fill in the missing dates.
  5 commentaires
Mohammad Sayeed
Mohammad Sayeed le 26 Mar 2015
Sorry for that. I have clearly attached EXCEL files in my comments but I don't know why these files are not shown.
Mohammad Sayeed
Mohammad Sayeed le 26 Mar 2015
I have attached them again. Hope this time it is okay. In the 1st sheet of the first file I have a very small sample of the original data that I have downloaded. In the second Sheet of this file I have shown how I need the data set to be. The second file shows how the first three time columns should look like in my intended data set. Thank you.

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