Extract positive value from solve function

29 vues (au cours des 30 derniers jours)
Sashi Mendoza
Sashi Mendoza le 3 Avr 2022
Modifié(e) : Sashi Mendoza le 21 Avr 2022
eqs = [(A-a1) == d, (A-a2) == d2;
S = solve(eqs, [A B]);
a = S.A
b = S.B
In the code above, all other variables are given so i AM solving for A and B. The code above alrEADY works and displays a solution but how will I extract the positive values of the solution only , and assign them to variables a and b?

Réponses (1)

Torsten
Torsten le 3 Avr 2022
Modifié(e) : Torsten le 3 Avr 2022
If a and b contain no more symbolic constants, then you can use
a = double(a);
b = double(b);
a = a(abs(imag(a)) < 1e-6);
b = b(abs(imag(b)) < 1e-6);
a = real(a);
b = real(b);
A = [];
B = [];
iter = 0;
for i = 1:numel(a)
if a(i) >= 0 && b(i) >= 0
iter = iter + 1;
A(iter) = a(i);
B(iter) = b(i);
end
end
A
B
  2 commentaires
Sashi Mendoza
Sashi Mendoza le 3 Avr 2022
Modifié(e) : Sashi Mendoza le 3 Avr 2022
I tried inputting this, but hte code still yields 2 answers each for A and B
A =
0.8465 + 0.3307i
0.8465 - 0.3307i
B =
0.4579 - 0.2660i
0.4579 + 0.2660i
Torsten
Torsten le 3 Avr 2022
Modifié(e) : Torsten le 3 Avr 2022
Since you get complex solutions to your system, the two circles don't cross for the midpoints and radii given.
In order that they have points in common, the condition
d + d2 >= sqrt((a1-a2)^2 + (c1-c2)^2)
must be met.
I modified the code from above.

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