How to convert a col array into a struct array field?

I have an struct array with multiplie fields and i want to assign a new field wich values come from a col array of a function.

Example:

Supose that my function returns "a"

a = [1; 2; 3; 4; 5; 6; 7; 8; 9; 10]

empty_test.a = [];
empty_test.b = [];

test = repmat(empty_test, size(a,1),1);

test.a = a; % Wrong

I want something like this as a result:

test(1).a = 1;
test(2).a = 2;
...
test(10).a = 10;

Answer 1

[Voss]

a = [1; 2; 3; 4; 5; 6; 7; 8; 9; 10];

% 10-by-1 struct array (doesn't need to have a field 
% 'a' - doesn't need to have any fields at all in fact):
test = repmat(struct('b',[]),numel(a),1)

test = 10×1 struct array with fields:
    b

% assign each element of a to field 'a' of corresponding element of test:
C = num2cell(a);
[test.a] = C{:};

% check the first couple:
test(1)

ans = struct with fields:
    b: []
    a: 1

test(2)

ans = struct with fields:
    b: []
    a: 2

[Vinicius Almeida]

thanks a lot, num2cell is the answer, because my struct already existed before creating "a"