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Output cell values and column number for matrix with specific values

3 vues (au cours des 30 derniers jours)
Emma Kuttler
Emma Kuttler le 18 Avr 2022
Modifié(e) : Stephen23 le 19 Avr 2022
Hi,
I have a 105 x 13 matrix where the first two columns represent an identifier and columns 3:13 have values either 0 or 1. What I'd like to do is output the first two columns, and then the column number for cells that have a value of 1. I'd like the column numbering to start at column 3, however, so something that is in actual column 13 should have the value 11.
For example, if this is my matrix A I want to produce B:
A = [ 1 128 1 0 0 0 0 0 0 0 0 0 0
1 129 0 1 1 1 0 1 1 0 0 0 1
1 130 1 0 1 0 0 0 0 1 0 0 0
1 149 0 0 0 0 1 0 1 1 0 0 0
1 150 1 1 0 0 1 1 1 0 0 0 0
1 154 1 1 1 1 1 1 0 0 1 1 1]
% I'd like to produce a matrix of the "locations" of the 1 values in
% columns 3:13.
B =
[1 128 1
1 129 2
1 129 3
1 129 4
1 129 6
1 129 7
1 129 11
1 130 1 . . ]

Réponses (2)

Voss
Voss le 18 Avr 2022
A = [1 128 1 0 0 0 0 0 0 0 0 0 0
1 129 0 1 1 1 0 1 1 0 0 0 1
1 130 1 0 1 0 0 0 0 1 0 0 0
1 149 0 0 0 0 1 0 1 1 0 0 0
1 150 1 1 0 0 1 1 1 0 0 0 0
1 154 1 1 1 1 1 1 0 0 1 1 1];
B = A(:,[1 2]);
A(:,[1 2]) = [];
[c,r] = find(A.');
B = [B(r,:) c]
B = 27×3
1 128 1 1 129 2 1 129 3 1 129 4 1 129 6 1 129 7 1 129 11 1 130 1 1 130 3 1 130 8

Stephen23
Stephen23 le 19 Avr 2022
Modifié(e) : Stephen23 le 19 Avr 2022
Without changing the input matrix A:
A = [1,128,1,0,0,0,0,0,0,0,0,0,0;1,129,0,1,1,1,0,1,1,0,0,0,1;1,130,1,0,1,0,0,0,0,1,0,0,0;1,149,0,0,0,0,1,0,1,1,0,0,0;1,150,1,1,0,0,1,1,1,0,0,0,0;1,154,1,1,1,1,1,1,0,0,1,1,1]
A = 6×13
1 128 1 0 0 0 0 0 0 0 0 0 0 1 129 0 1 1 1 0 1 1 0 0 0 1 1 130 1 0 1 0 0 0 0 1 0 0 0 1 149 0 0 0 0 1 0 1 1 0 0 0 1 150 1 1 0 0 1 1 1 0 0 0 0 1 154 1 1 1 1 1 1 0 0 1 1 1
M = A(:,3:end).';
[C,R] = find(M);
B = [A(R,1:2),C]
B = 27×3
1 128 1 1 129 2 1 129 3 1 129 4 1 129 6 1 129 7 1 129 11 1 130 1 1 130 3 1 130 8

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