Output cell values and column number for matrix with specific values

Hi,

I have a 105 x 13 matrix where the first two columns represent an identifier and columns 3:13 have values either 0 or 1. What I'd like to do is output the first two columns, and then the column number for cells that have a value of 1. I'd like the column numbering to start at column 3, however, so something that is in actual column 13 should have the value 11.

For example, if this is my matrix A I want to produce B:

A = [ 1	128	1	0	0	0	0	0	0	0	0	0	0
     1	129	0	1	1	1	0	1	1	0	0	0	1
     1	130	1	0	1	0	0	0	0	1	0	0	0
     1	149	0	0	0	0	1	0	1	1	0	0	0
     1	150	1	1	0	0	1	1	1	0	0	0	0
     1	154	1	1	1	1	1	1	0	0	1	1	1]

% I'd like to produce a matrix of the "locations" of the 1 values in
% columns 3:13. 

B = 
[1 128 1
 1 129 2
 1 129 3
 1 129 4
 1 129 6
 1 129 7
 1 129 11
 1 130 1 . . ]

Answer 1

[Voss]

A = [1	128	1	0	0	0	0	0	0	0	0	0	0
     1	129	0	1	1	1	0	1	1	0	0	0	1
     1	130	1	0	1	0	0	0	0	1	0	0	0
     1	149	0	0	0	0	1	0	1	1	0	0	0
     1	150	1	1	0	0	1	1	1	0	0	0	0
     1	154	1	1	1	1	1	1	0	0	1	1	1];

B = A(:,[1 2]);
A(:,[1 2]) = [];
[c,r] = find(A.');
B = [B(r,:) c]

B = 27×3

1 128 1 1 129 2 1 129 3 1 129 4 1 129 6 1 129 7 1 129 11 1 130 1 1 130 3 1 130 8

Answer 2

[Stephen23]

Without changing the input matrix A:

A = [1,128,1,0,0,0,0,0,0,0,0,0,0;1,129,0,1,1,1,0,1,1,0,0,0,1;1,130,1,0,1,0,0,0,0,1,0,0,0;1,149,0,0,0,0,1,0,1,1,0,0,0;1,150,1,1,0,0,1,1,1,0,0,0,0;1,154,1,1,1,1,1,1,0,0,1,1,1]

A = 6×13

1 128 1 0 0 0 0 0 0 0 0 0 0 1 129 0 1 1 1 0 1 1 0 0 0 1 1 130 1 0 1 0 0 0 0 1 0 0 0 1 149 0 0 0 0 1 0 1 1 0 0 0 1 150 1 1 0 0 1 1 1 0 0 0 0 1 154 1 1 1 1 1 1 0 0 1 1 1

M = A(:,3:end).';
[C,R] = find(M);
B = [A(R,1:2),C]

B = 27×3

1 128 1 1 129 2 1 129 3 1 129 4 1 129 6 1 129 7 1 129 11 1 130 1 1 130 3 1 130 8