Why I see only the last value of my row vector in the workspace?

I have the following row vectors in my program:

When I run my program, I see in the workspace only the last value of these row vectors as :

I don't know whether my program executes using only the last values of these row vectors or all. What modification my program needs so that I can see all these row vectors in my workspace instead of a singla value? My program is:

clear all; close all; clc; 

cloud = 'Homo';
T_para = zeros(5, 17, 20);
T_per = zeros(5, 17, 20);
cth=[1010:10:1200]
h = [1000:1000:4000];
a = [0.01:0.01:0.05];
r = [4:1:20];
fov = [0.2 0.5 1 2 5 10]
snr=[30 40 50 65 75];
for h = 1000:1000:4000
    for fov = [0.2 0.5 1 2, 5 10]
        dir_arhf = ['Tabledata_', cloud, '\', num2str(h), 'm-', num2str(fov), 'mrad'];
        mkdir(dir_arhf);
        for a = 0.01:0.01:0.05
            for r = 4:1:20
                load (['MCdatabase_', cloud, '/', num2str(a), '-', num2str(r), 'um/', num2str(h), 'm-', num2str(fov), 'mrad/I0.mat']);
                load (['MCdatabase_', cloud, '/', num2str(a), '-', num2str(r), 'um/', num2str(h), 'm-', num2str(fov), 'mrad/Q0.mat']);
                I_para = 1/2 * (I0 + Q0);
                I_per = 1/2 * (I0 - Q0);
                hh = genHeight(h).^2;
                beta_para = sum(I_para, 2) .* hh';
                beta_per = sum(I_per, 2) .* hh';
                T_para(a * 100, r-3, :) = beta_para';
                T_per(a * 100, r-3, :) = beta_per';
                Norm_para(a * 100, r-3, :)=(T_para(a * 100, r-3, :)./max(T_para(a * 100, r-3, :)));
                Norm_per(a * 100, r-3, :)=(T_per(a * 100, r-3, :)./max(T_per(a * 100, r-3, :)));
                for snr=[30, 40, 50, 65, 75]
                    snr_para(a * 100, r-3, :)=awgn(T_para(a * 100, r-3, :),snr);
                    snr_per(a * 100, r-3, :)=awgn(T_per(a * 100, r-3, :),snr);
                    costf=sqrt((snr_para(a * 100, r-3, :)-Norm_para(a * 100, r-3, :)).^2+(snr_per(a * 100, r-3, :)-Norm_per(a * 100, r-3, :)).^2);
                    save([dir_arhf, '\TABLE.mat'], 'T_per', 'T_para');
                end
            end
        end
    end
end

[Stephen23]

Look at your FOR loops:

h = [1000:1000:4000]; % this is totally unused
..
for h = 1000:1000:4000 % becaue you redefined h here

The same for all of those other variables.

Answer 1

[KSSV]

You are using the vector as the loop index so obviously you will find only the last value. You can check it your self.

for a = 0.01:0.01:0.05
    a
end

a = 0.0100

a = 0.0200

a = 0.0300

a = 0.0400

a = 0.0500

fprintf('%f\n',a)

0.050000

You see, only the last value is printed, as it is the last index value. If you want it as a vector, you need to run like shown below.

a = 0.01:0.01:0.05;
for i = 1:length(a)
    a(i)
end

ans = 0.0100

ans = 0.0200

ans = 0.0300

ans = 0.0400

ans = 0.0500

% after loop a
a

a = 1×5

0.0100 0.0200 0.0300 0.0400 0.0500

[Wiqas Ahmad]

This works well. Thank you so much.