column number extract using find function..
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
A = [ 0 500 1000 1500 2000 2500 3000 3500 x1 x2 x3 5500 6000 6500 7000 7500 8000 8500 9000 9500 10000 ] ;
i want to know the column number using find function about 500,1000,2000,3000, x2, 4000, 5000, 6000, 7000, 8000, 9000, 10000 ].
like above answer B
: B = [ 2 3 5 7 9 11 13 15 17 19 21 23 25 27 29 ] ; (example : it's not answer)
The x1, x2, x3 is variable value.
0 commentaires
Réponses (3)
dpb
le 6 Mai 2022
Use the optional second output form of find
[r,c]=find(....);
1 commentaire
Jon
le 6 Mai 2022
Modifié(e) : Jon
le 6 Mai 2022
I think this seems like it would only help you if you had a 2d array of logicals or 0's and 1's. The OP just has a 1d array. Unless maybe I am completely missing something. The issue is how to create the corresponding vector of logicals that find can be applied to. One way is using ismember as shown in my answer below.
Jon
le 6 Mai 2022
A = [ 0 500 1000 1500 2000 2500 3000 3500 x1 x2 x3 5500 6000 6500 7000 7500 8000 8500 9000 9500 10000 ] ;
matchVals = [500,1000,2000,3000, x2, 4000, 5000, 6000, 7000, 8000, 9000, 10000 ];
B = find(ismember(A,matchVals))
1 commentaire
Jon
le 6 Mai 2022
In your case the values seem to follow a very regular progression. I'm not sure if this is just the case for the example you give or if it always holds. If you have such a regular progression you could also write a formulae, e.g
B = matchVals/500 + 1
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!