break from a nested for loop
23 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
kurdistan mohsin
le 10 Mai 2022
Commenté : kurdistan mohsin
le 16 Mai 2022
hi, i have the below matrix , i want each row to have only on value equal to '1' , so when searching if it find a one it will take it and make the rest values of the row equal to zero . i write the bellow code , i need to break the second loop when the if condtion is true , any one can help?
D=[ 1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
0 1 0 0 0
1 1 0 1 1
0 0 1 0 0
0 0 0 0 0
0 0 1 0 0
1 0 0 1 1
0 0 0 0 0]
N=10;
M=5;
for n=1:N
for m=1:M
if D(n,m)==1
Dn(n,m)=1;
Dn(n,m+1:end)=0;
else Dn(n,m)=0;
end
end
end
Dn
0 commentaires
Réponse acceptée
Image Analyst
le 10 Mai 2022
Try using a flag
abort = false;
for n = 1 : N
for m = 1 : M
if conditionForBreaking
abort = true; % Set flag
break; % Exit inner loop.
end
end
if abort
break % exit outer loop.
end
end
3 commentaires
Image Analyst
le 11 Mai 2022
D=[ 1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
0 1 0 0 0
1 1 0 1 1
0 0 1 0 0
0 0 0 0 0
0 0 1 0 0
1 0 0 1 1
0 0 0 0 0];
[rows, columns] = size(D);
for row = 1 : rows
indexOfFirst1 = find(D(row,:) == 1, 1, 'first');
if ~isempty(indexOfFirst1)
% If there is a one in the row, make all elements
% in the row zero after that one.
D(row, indexOfFirst1+1:end) = 0;
end
end
D
Plus de réponses (1)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!