Effacer les filtres
Effacer les filtres

separate rain events by specific dry period

1 vue (au cours des 30 derniers jours)
Albert Johan Mamani Larico
Commenté : Jovon Jacob le 8 Jan 2023
Hi
I have hourly rain data for a period of 5 years
x = [0 0 0 0 0 2 4 5 14 10 16 0 0 0 0 0 24 33 22 0 0 2 3 5 0 0 0 0.........]
I need to group them considering that each rain event is separated by 3 hours of zero values or more
How could I get the numbers of rain events, their mean rain value and duration of each event?

Réponse acceptée

Image Analyst
Image Analyst le 12 Mai 2022
Try this, if you have the Image Processing Toolbox.
x = [0 0 0 0 0 2 4 5 14 10 16 0 0 0 0 0 24 33 22 0 0 2 3 5 0 0 0 0]
props = regionprops(x > 0, x, 'Area', 'MeanIntensity')
numberOfRainPeriods = length(props)
stormLengths = [props.Area] % In hours
meanRainPerHour = [props.MeanIntensity] % In mm or whatever.
integratedRainTotalsPerStorm = stormLengths .* meanRainPerHour % In mm or whatever.
You get
numberOfRainPeriods =
3
stormLengths =
6 3 3
meanRainPerHour =
8.5 26.333 3.3333
integratedRainTotalsPerStorm =
51 79 10
  3 commentaires
Image Analyst
Image Analyst le 7 Jan 2023
@Jovon Jacob give an example. Input, and output vectors. Best if you start your own thread and attach this code as your starting code.
Jovon Jacob
Jovon Jacob le 8 Jan 2023

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