replace matrix A with the values of another matrix B

Having a matrix A as attached, how to replace all those 1 in A with the values in matrix B, so that i get a new matrix as newA

A(:,:,1) =

0   0   1
0   1   0
0   1   1


A(:,:,2) =

1   0   0
0   0   0
0   0   0


A(:,:,3) =

0   1   0
1   0   1
1   0   0

B = [6 1 5; 2 6 7; 4 6 9];
B =

6     1     5
2     6     7
4     6     9

newA(:,:,1) =

0   0   5
0   6   0
0   6   9


newA(:,:,2) =

6   0   0
0   0   0
0   0   0


newA(:,:,3) =

0   1   0
2   0   7
4   0   0

Answer 1

[Bruno Luong]

A= cat(3, [ 0   0   1;
    0   1   0;
    0   1   1], ...
    [1   0   0,
    0   0   0;
    0   0   0], ...
    [0   1   0;
    1   0   1;
    1   0   0 ]);
B = [6 1 5; 2 6 7; 4 6 9];

A.*B

ans = 
ans(:,:,1) =

     0     0     5
     0     6     0
     0     6     9


ans(:,:,2) =

     6     0     0
     0     0     0
     0     0     0


ans(:,:,3) =

     0     1     0
     2     0     7
     4     0     0

Answer 2

[Dyuman Joshi]

A(:,:,1) = [0   0   1; 0   1   0; 0   1   1];
A(:,:,2) = [1   0   0; 0   0   0; 0   0   0];
A(:,:,3) = [0   1   0; 1   0   1; 1   0   0];

B = [6 1 5; 2 6 7; 4 6 9];

newA=A.*B

newA = 
newA(:,:,1) =

     0     0     5
     0     6     0
     0     6     9


newA(:,:,2) =

     6     0     0
     0     0     0
     0     0     0


newA(:,:,3) =

     0     1     0
     2     0     7
     4     0     0