Find the corresponding value of y when x is a specific value?

I have a 369 x 2 x 27 matrix. The 369 rows (x value) are from 230:598. I want to find the corresponding y value when x-value is equal 280. Then, make a table with 1:27 on the first column and the corresponding values as the second column. Can anyone please advice me how to do it?

Thank you so much!!

Answer 1

[Voss]

Maybe this

% a 3D array like yours
M = [(230:598).' rand(369,1)]+reshape(0:5:130,[1 1 27]);
size(M)

ans = 1×3

369 2 27

% find the row of M(:,1,1) where 280 is
row_idx = find(M(:,1,1) == 280,1);

% make the table
T = table((1:size(M,3)).',permute(M(row_idx,2,:),[3 2 1]));
head(T)

ans = 8×2 table
    Var1     Var2 
    ____    ______

     1      0.6688
     2      5.6688
     3      10.669
     4      15.669
     5      20.669
     6      25.669
     7      30.669
     8      35.669

[Cheuk Yin Wong]

Thank you so much! It works very well.

[Voss]

You're welcome!