Rounding off to odd multiples of 25
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variable X varies as 25:50:125875
A= "Enter a value of X"
I must round off the value of A (user input) to match certain X value.
I need if A = anything ending with 75 or 25 : aceept it if A = anything ending with values(26-49) : floor it to the value ending with 25, just before if A = anything ending with values(51-74) : ceiling it to the value ending with 75, just after
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Guillaume
le 28 Jan 2015
It's fairly straightforward, subtract 25, divide by 50, round to nearest integer and then multiply back by 50 and readd the 25:
>>roundspecial = @(x) 25+50.*round((x-25)./50);
>>roundspecial(25)
ans =
25
>>rounspecial(26)
ans =
25
>>roundspecial(49)
ans =
25
>>roundspecial(50)
ans =
75
>>roundspecial(374)
ans =
375
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