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How to generate series by percentage difference using loop?

1 vue (au cours des 30 derniers jours)
Triveni
Triveni le 22 Juin 2022
Commenté : Triveni le 24 Juin 2022
I have a value
A(1) = 60;
A(2) = A(1) *0.99;
A(3) = A(2) *0.99;
A(4) = A(3) *0.99;
A(5) = A(4) *0.99;
A(6) = A(5) *0.98; % Values changing after 5 iteration
.
.
.
A(11) = A(10) *0.97; % Values changing after 5 iteration
.
.
.
.till the differences reached to 0.01.
Please help me.

Réponse acceptée

KSSV
KSSV le 22 Juin 2022
Modifié(e) : KSSV le 22 Juin 2022
A = zeros([],1) ;
A(1) = 60 ;
dA = 1 ;
i = 1 ;
while dA > 0.01
i = i+1 ;
A(i) = A(i-1)*0.99 ;
dA = abs(A(i)-A(i-1)) ;
end
  4 commentaires
Triveni
Triveni le 23 Juin 2022
Value of .99 is not changing after 5th iteration. Means A(6) = A(5) *0.98; please correct.
Triveni
Triveni le 24 Juin 2022
%----------------------------------------
PP = 28;
sdf = 0.995;
%----------------------------------------
%Generate Series
A = zeros([],1) ;
A(1) = PP;
dA = 1 ;
i = 1 ;
while dA > 0.0001
i = i+1 ;
if length(A)>4 && rem(length(A),5)==0
sdf = sdf-.01;
A(i) = A(i-1)*sdf ;
else
A(i) = A(i-1)*sdf ;
end
dA = abs(A(i)-A(i-1)) ;
end
A = round(unique(A'),2);
A = A(fliplr(1:end),:);
N = 0.05; % Round value
B = unique(nonzeros(round(A/N)*N));
A = B(fliplr(1:end),:);

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