# how to range data and find maximum value for each range by using loop

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abdullah al-dulaimi le 29 Juin 2022
I have data (AB) consisting of two columns. The number of rows of this data is 80315. I want to divide this number into (1: 2000: 80315) and take the maximum values for each period (based on the second column, also i want to index the firt colum).
I using this code but its very long.
a = AB([1:2000],:);
aa=max(a);
a1 = AB([2000:4000],:);
aa1=max(a1);
a11 = AB([4000:6000],:);
aa11=max(a11);
maxvalues=([aa;aa1;aa11])
##### 2 commentairesAfficher AucuneMasquer Aucune
Pooja Kumari le 29 Juin 2022
According to your code, you want to get maximum value for each period, what do you mean by second column?
abdullah al-dulaimi le 29 Juin 2022
i mean the output will be 2 coluoms not 1

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### Réponse acceptée

Pooja Kumari le 29 Juin 2022
Modifié(e) : Pooja Kumari le 29 Juin 2022
It is my understanding that you are facing issues with huge vector and instead of hardcoding, you want a generalized form of code for taking the maximum value for your data for each period by taking 2000 data at a time out of 80315 rows of data.
Please find below an example code for the same with random dataset of 80315 rows and 2 columns:
data = rand(80315,2); %data
index = 1;
for i = 1:1999:80315-1999
array_data = data(i:i+1999,:); %data is divided into %2000 samples at a time.
output(index,1) = max(array_data(:)); %taking max of all values in a period
index = index +1;
end
Sincerely,
Pooja Kumari
##### 1 commentaireAfficher -1 commentaires plus anciensMasquer -1 commentaires plus anciens
abdullah al-dulaimi le 29 Juin 2022
dear Pooja Kumari ,
Thank you for your kind efforts.
best regard

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