The program cannot work
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hi.
There is a review question without answer.
Here is the question
A function is defined as
function [dice] = roll(sides)
dice(0) = randi(sides);
dice(1) = randi(sides);
end
If the function is called as follows:
[roll1,roll2] = dice(6);
and the random numbers generated are 1 and 6. What will be the value od roll1 and roll2?
My first question is that what is roll1 and roll2? i confused for the function. the return value is only one, why it can be returned two values as roll1 and roll2 ?
Then, the function name is roll, why use dice to call the function?
Thank you all.
0 commentaires
Réponse acceptée
Siraj
le 4 Juil 2022
Modifié(e) : Siraj
le 4 Juil 2022
Hi,
It is my understanding that you want to know the value of roll1 and roll2,
“[roll1, roll2] = dice (6)”.
This will lead to an “Too many output arguments” error because the function has only one return object that is “dice”.
The name of the function is “roll” therefore we cannot call the function using “dice()”.
The correct way to call the function is “d = roll(6) “ where “d” is a random integer array of dimension 1X2 and values in range 1 to 6.
d = roll(6)
function [dice] = roll(sides)
dice(1) = randi(sides);
dice(2) = randi(sides);
end
Plus de réponses (1)
Chunru
le 4 Juil 2022
Modifié(e) : Chunru
le 4 Juil 2022
% [roll1,roll2] = dice(6)
% The above is wrong in syntax as the function has only ONE return object
% dice (as an array).
% The correct way to call the function
d = roll(6)
function [dice] = roll(sides)
% dice(0) = randi(sides);
% dice(1) = randi(sides);
dice = randi([1 6], [2 1]); % generate 2x1 random integer in range [1 6]
end
Voir également
Catégories
En savoir plus sur Introduction to Installation and Licensing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!