reduce values on a vector

Hey guys,

I have this code. This two signal have a lot of values(millions) I want to use 1000 values(reference_signal_samples and Surveillance_signal_samples) with a step of 3000 samples. Im not able to do it with this code, I dont know where the error is.

Thank you

nRef = numel(Reference_signal)/Fs;
nSurv = numel(Surveillance_signal)/Fs;
pulse_size = 1000;
for k = 1:nRef
    Reference_signal_samples =Reference_signal((k-1)*pulse_size+(1:pulse_size));
    
    for kk =1:nSurv

    Surveillance_signal_samples=Surveillance_signal((kk-1)*pulse_size+(1:pulse_size));
    end
    
end

Answer 1

[Jan]

You are overwriting the variable Surveillance_signal_samples repeatedly:

for kk =1:nSurv
    Surveillance_signal_samples=Surveillance_signal((kk-1)*pulse_size+(1:pulse_size));
end

You want to use 1000 values with a stepwidth of 3000?

Reference_signal_samples = Reference_signal(1:3000:3000*1000);
Surveillance_signal_samples = Surveillance_signal(1:3000:3000*1000);

No loops.

A hint: Use more compact names for variablkes to improve the readability.

[Miguel Albuquerque]

sorry, shoudnt it be?

And with that code, than I have to change the values, because next I want the iteration 4000 to 5000

I want first Reference_signal_samples(1:1000), plot the signals, next Reference_signal_samples(4000:5000), plot the signals, till the end of samples(millions)

Reference_signal_samples = Reference_signal(1:3000:3000);

[Jan]

Maybe I've misunderstood your question.

disp(1:3000:3000)

     1

1:3000:3000 is the scalar 1. If you really want to get parts of the array, these indices are strange: 1:1000, 4000:5000 : The 2nd has 1001 elements, the first only 1000. Maybe you mean:

for k = 1:4000:numel(Reference_signal)
    signal = Reference_signal(k:k+999);
    ... here your calculations...
end