Save folder one above current directory

Let's say I am working in the directory:
/home/username/Matlab/
I want to save (in a script) the directory one above the one I am working in (to use it later in the script), so:
newdir='home/username';
But I am working in different computers, so the 'username' changes, thus I want to do it automatically, such as save "newdir" as "one above the current directory".
Thank you

 Réponse acceptée

Jan
Jan le 7 Fév 2015
Folder = cd;
Folder = fullfile(Folder, '..');
save(fullfile(Folder, 'FileName.mat'))

11 commentaires

Zynk
Zynk le 9 Fév 2015
Thanks for your answer. It works, but I prefer the method given by Geoff.
Jan
Jan le 9 Fév 2015
Modifié(e) : Jan le 9 Fév 2015
The ".."-method works correctly if you are in a root folder like "C:\" already and it considers even UNC-paths like "\\server\folder\". It works under Windows and Linux.
Stephen23
Stephen23 le 9 Fév 2015
This is the more universal solution. Use this.
fullfile(cd, '..')
gives only the current directory, and added a file separator and the two dots to it. This correlates with the matlab documentation for fullfile:
"Relative directories indicated by the double-dot symbol are not collapsed."
Tested on Matlab 2017b, Windows 10.
Is there a working solution?
Stephen23
Stephen23 le 27 Août 2019
Modifié(e) : Stephen23 le 1 Juil 2021
"Is there a working solution?"
To what? Relative filenames work perfectly with MATLAB, so to read/write data files it is not neccesary to "collapse" anything, you can simply use '..' by themselves (or append them to pwd, or even better with '.' to specify the current directory). Using a relative path with '..' answers the original question.
If you really want to get the absolute path, just use fileparts on the string returned by pwd.
Ryan Budde
Ryan Budde le 9 Déc 2020
Modifié(e) : Ryan Budde le 9 Déc 2020
To load a file in Windows 10, I needed the following in order for it to work. Assuming the following folder structure:
ParentFolder>
Subfolder1
Subfolder2
Where Subfolder1 contains the file of interest and Subfolder2 is the current working directory. In this scenario, the following works:
fn = cd;
fn = fullfile(fn, '..');
fn = [fn '\Subfolder1\fileOfInterest.mat'];
data = load(fn);
Cecilia S.
Cecilia S. le 16 Juin 2021
this does not work in new versions of matlab, fullfile() recognises ".." as a folder name and not a "command" to go back one folder, so it creates a path using like this: "Folder/.."
Stephen23
Stephen23 le 17 Juin 2021
Modifié(e) : Stephen23 le 17 Juin 2021
@Cecilia S: that is the intended behavior of FULLFILE, exactly as it is documented. It is the OS that assigns meaning to '..', once the path is actually supplied to the OS (e.g. to read/write a file), not FULLFILE.
This is exactly the same as if you were to hard-write a path using '..' somewhere in the folder heirarchy.
So your comment is incorrect: FULLFILE still works correctly, even for "new versions" of MATLAB. You just don't understand how path resolution works, but luckily the people who wrote FULLFILE do:
What you ask for is anyway impossible: for example, only the OS can resolve this path:
./../../..
FULLFILE does not (and never has, probably never will) actually check if a path exists or is valid on a particular location, nor would this be a useful design (slow, device dependent, superfluous, meaningless if a path is yet to be created). Only the OS can do this, which is why the OS resolves both the dot and dotdot folders:
Using dot and dotdot is the designed, best method to refer to the current and parent (of any) directories.
EagleGB
EagleGB le 18 Août 2022
I'm on a Mac, working in AppDesigner. I am having a similar issue. If I append a '..' to the filename, it works to go up one folder in terminal and in the file directory bar in MATLAB. But when I try to do the same thing in uigetfile, it doesn't go up one directory:
DefOutputDirectory = fullfile(app.outputDirectory,'..');
[NewFile,NewPath] = uigetfile('*.*','Select Destination Folder for Results',DefOutputDirectory);
This just points uigetfile to the directory in app.outputDirectory. Is this a problem with the way uigetfile works?
Stephen23
Stephen23 le 19 Août 2022
Modifié(e) : Stephen23 le 19 Août 2022
"Is this a problem with the way uigetfile works?"
No, there is no problem with how UIGETFILE works. The UIGETFILE documentation states "To specify a folder name only, make the last character of the defname value either a backslash (\) or a slash (/)."
Once you add the trailing fileseparator it will work as you require and as documented. As an alternative, if you are using FULLFILE it might be easier to add a trailing asterisk like this:
fullfile(..,'..','*')
EagleGB
EagleGB le 2 Sep 2022
Thanks Stephen. Adding the '*' to the end of the fullfile string worked for me.

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Plus de réponses (3)

Geoff Hayes
Geoff Hayes le 7 Fév 2015
Zynk - try using pwd with strfind to determine the index of the last occurrence of the slash /. Then just remove it and everything that follows. Something like
mydir = pwd;
idcs = strfind(mydir,'/');
newdir = mydir(1:idcs(end)-1);
Try the above (or a variation of it) and see what happens!

2 commentaires

I would set the 2nd line of answer to:
idcs = strfind(mydir,filesep);
in case running code on Windows. Very useful method, incorporating it into my code right now.
YT
YT le 31 Jan 2019
Agree with @JSPERNY. This method also works with Matlab Online (unlike @Jan's answer).

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Ivan Nascimento
Ivan Nascimento le 30 Juin 2021
An alternative solution, as pointed out by Stephen in the comments, is to use fileparts with cd (or pwd) to get the directory above the current. It might be useful depending on the context, as it was for me (R2016a) and seems to be for Cecilia, so here it is.
parentDirectory = fileparts(cd); % also works with pwd instead of cd
If you intend to use the saved string in a different platform, make sure the path delimiters are consistent with the platform. Specifically, you will have trouble from Windows to Unix or Mac systems because on Windows fileparts adopts backslashes by default. The other way around is fine because on Windows you can use either forward (/) or back (\) slashes as path delimiters, according to the fileparts documentation.

1 commentaire

Stephen23
Stephen23 le 1 Juil 2021
Modifié(e) : Stephen23 le 1 Juil 2021
The simple, efficient, robust solution is to just use '..' to refer to the parent directory.
"If you intend to use the saved string in a different platform..."
.. .then you can trivially avoid all of that worrying and messing about with path delimiters by using '.' to refer to the current directory, and '..' to its parent. This will work correctly for MATLAB R2016a (and every other version of MATLAB too) on any platform:
fullfile('.','..',nameofmyfile)

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Walter Adame Gonzalez
Walter Adame Gonzalez le 9 Août 2022
Modifié(e) : Walter Adame Gonzalez le 9 Août 2022

0 votes

Try using the following function
syntax:
newDir = getParentDir(dir, numUpDirs);

1 commentaire

Stephen23
Stephen23 le 9 Août 2022
Modifié(e) : Stephen23 le 9 Août 2022
Note that GETPARENTDIR does not work with relative directories, nor with dot directory names:
It also hardcodes a backslash file separator (rather than being OS agnostic by using FILESEP or FILEPARTS).

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