Code sigadd help me

function [x, n] = signalplus(s1, n1, s2, n2)
% n1 is the sample positions of s1
% n2 is the sample positions of s2

i understood it but i can write in matlab

example:

 s1=[2 5 7]; n1=2
 s2=[3 2 6]; n2=3
 s=s1 + s2 = [3 4 11 7]

thank you :)

i find a code but it not work , i use : sigadd([2 5 7],2,[3 2 6],3) error

function [y,n] = sigadd(x1,n1,x2,n2)

% implements y(n) = x1(n)+x2(n)

% -----------------------------

% [y,n] = sigadd(x1,n1,x2,n2)

%   y = sum sequence over n, which includes n1 and n2

%  x1 = first sequence over n1

%  x2 = second sequence over n2 (n2 can be different from n1)

%

n = min(min(n1),min(n2)):max(max(n1),max(n2)); % duration of y(n)

y1 = zeros(1,length(n)); y2 = y1;              % initialization

y1(find((n>=min(n1))&(n<=max(n1))==1))=x1;     % x1 with duration of y

y2(find((n>=min(n2))&(n<=max(n2))==1))=x2;     % x2 with duration of y

y = y1+y2;                                     % sequence addition

Answer 1

[Geoff Hayes]

Syren - presumably you found sigadd.m from the submission by John Proakis at DSP Using MATLAB. In the Chapter 2 folder (CHAP_02/) there is an example file called ex020200.m which invokes the sigadd function as

 [x1,n1] = sigadd(2*x11,n11,-3*x12,n12);

where each of the input vectors are 1x13 arrays. I suspect that you will need to do something similar in your example. The n1 and n2 inputs (your 2 and 3) should be arrays such as

 n1 = [1 2 3];
 n2 = [0 1 2];

with

sigadd([2 5 7],[1 2 3],[3 2 6],[0 1 2])

producing the desired output of

 ans =
     3     4    11     7

Try the above and see what happens!

[Syren Py]

ok,thank you :)

Answer 2

[Chidiebere Onuoha]

%I hope this will help:

    %implements y(n)=x1(n)+x2(n)
    % y = sums  the sequence over n, which includes n1 and n2
    %x1 = first sequence over n1
    %x2 = second sequence over n2

    function [y,n] = sigadd(x1,x2,n1,n2)
    n = min(min(n1), min(n2)): max(max(n1),max(n2));
    %duration of y(n)

   y1 = zeros(1, length(n));
   y2 = y1; 
   %initialization

   y1(find((n>=min(n1))&(n<=max(n1))==1)) = x1; 
   % x1 with duration of y

   y2(find((n>=min(n2))&(n<=max(n2))==1)) = x2; 
   % x2 with duration of y

   y = y1+y2; 
   %sequence addition

end

[Azmat Ameen]

error: not enough input argument.

please guide

[Geoff Hayes]

Azmat - please post the full error message and line of code that is generating the error. Also, are you passing the correct/expected number of input arguments into whichever function that you are calling?

[Nga Ly]

Not enough input arguments.

Error in sigadd (line 4)

n=min(min(n1),min(n2)):max(max(n1),max(n2));

Answer 3

[buynaa]

x_1-x_2-5→max

〖〖(x〗_1-1)〗_2≤1

〖x_1+x〗_2≥3,5

0≤x_1≤5

0≤x_2≤5