Find Max values in each row

15 vues (au cours des 30 derniers jours)
Learning
Learning le 18 Juil 2022
Commenté : Voss le 19 Juil 2022
Hi everyone, I have a Matlab question and I'm having some issues...
I have data (please see the data above) known as A1. I have 3 rows but row one is just the x-axis. I want to extract the max value in each row (rows 2 and 3) as well as the associated x-axis (row 1) value for each max value. The code I'm using is below:
[maxA1, index] = max(A1,[],2);
In this case, maxA1 rightfully gives me 1.6 and 2.3 as the max values for rows 2 an 3 respectfully. The index value is giving me just the column numbers (i.e., 4 or D in the case of excel and 3 or C in the case of excel). In reality, I am not interested in the column #s, I was hoping to get the corresponding x-axis values in row 1 instead (in this case, 500 and 400). I wouldn't mind to get the index/column #s as well but what I really need is the x-axis values.
Please is there a way or any suggestion on how the code can be modifie to give me the max values in rows 2 and 3 as well as their corresponding x-axis values (which is in row 1) and possibly the index/column number as well?
Thank you!

Réponse acceptée

Voss
Voss le 18 Juil 2022
A1 = [ ...
200 300 400 500 600; ...
1.2 1.3 1.4 1.6 1.2; ...
1.5 1.9 2.3 1.5 1.2];
Use the index you get to index into the first row of A1:
[maxA1, index] = max(A1,[],2)
maxA1 = 3×1
600.0000 1.6000 2.3000
index = 3×1
5 4 3
maxX = A1(1,index)
maxX = 1×3
600 500 400
(Same as above, except using only rows 2 through the end of A1:)
[maxA1, index] = max(A1(2:end,:),[],2)
maxA1 = 2×1
1.6000 2.3000
index = 2×1
4 3
maxX = A1(1,index)
maxX = 1×2
500 400
  2 commentaires
Learning
Learning le 19 Juil 2022
Thank you!!
Voss
Voss le 19 Juil 2022
You're welcome!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Produits


Version

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by