how can we use max function inside while loop ?

My question, can we choose the maximimum value out of the maxvalue as explained below the first maxvalue 4 the second maxvalue 8, the third maxvalue 3 the fourth maxvalue 2 and the fifth max value is 6. ??

thanks in advance

while true
    for i=1:20
        x= do calculation from 1 up to 20  % (1:20= we call it one round)
    end
    
    [maxvalue(i), indxmax] = max(x(:));
    maxvalue will be one value in each for loop round, but for loop will be repeated let say 5 times
    so, maxvalue will be 4 in first 20 step, 8 in the second 20, 3 in third round, and so forth
    up to 5 round 
    
    if x(i) >= maxvalue(i) % This condition to break the while loop
        break
    end
end

Answer 1

[David Hill]

count=1;
while 1
    for i=1:20
        x(i)= % calculations
    end
    
    maxvalue(count) = max(x);
    count=count+1;
    
    if x(end) == maxvalue(end)
        break
    end
end
max_maxvalue=max(maxvalue);

[omar th]

It's woked, thank you so much

[omar th]

David Hill , please would you tell how can I find the global max. For example, if we for loop iterate its self 5 times, so, maxvalue from these iteration is 8, 3, 4, 5,6, here the max_maxvalue consider only the last maxvalue as max_maxvalue not compare among the max value og the 5 iterations and consider 8 as the max_maxvalue, I dont know to make that