How to take average of such an array?

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Prashant Bhagat
Prashant Bhagat le 18 Août 2022
Réponse apportée : Stephen23 le 18 Août 2022
Z =
6×2 cell array
{[1 0 2 2 1 1 3 1 1 0]} {[2 1 0 0 0 1 0 2 0 0]}
{[2 2 3 3 1 3 3 2 1 0]} {[2 2 0 0 1 2 0 2 0 0]}
{[2 3 3 3 2 3 4 2 1 0]} {[3 5 0 0 1 3 0 3 0 1]}
{[2 3 3 5 2 3 6 3 1 1]} {[3 5 1 0 1 4 0 4 0 1]}
{[2 4 3 5 2 3 6 3 1 2]} {[4 5 2 0 1 5 0 5 2 2]}
{[2 5 3 7 3 4 6 3 1 3]} {[5 5 2 0 3 5 1 6 4 3]}

Réponse acceptée

Stephen23
Stephen23 le 18 Août 2022
Z = {[1,0,2,2,1,1,3,1,1,0],[2,1,0,0,0,1,0,2,0,0];[2,2,3,3,1,3,3,2,1,0],[2,2,0,0,1,2,0,2,0,0];[2,3,3,3,2,3,4,2,1,0],[3,5,0,0,1,3,0,3,0,1];[2,3,3,5,2,3,6,3,1,1],[3,5,1,0,1,4,0,4,0,1];[2,4,3,5,2,3,6,3,1,2],[4,5,2,0,1,5,0,5,2,2];[2,5,3,7,3,4,6,3,1,3],[5,5,2,0,3,5,1,6,4,3]}
Z = 6×2 cell array
{[1 0 2 2 1 1 3 1 1 0]} {[2 1 0 0 0 1 0 2 0 0]} {[2 2 3 3 1 3 3 2 1 0]} {[2 2 0 0 1 2 0 2 0 0]} {[2 3 3 3 2 3 4 2 1 0]} {[3 5 0 0 1 3 0 3 0 1]} {[2 3 3 5 2 3 6 3 1 1]} {[3 5 1 0 1 4 0 4 0 1]} {[2 4 3 5 2 3 6 3 1 2]} {[4 5 2 0 1 5 0 5 2 2]} {[2 5 3 7 3 4 6 3 1 3]} {[5 5 2 0 3 5 1 6 4 3]}
M = mean(cell2mat(permute(Z,[1,3,2])),3)
M = 6×10
1.5000 0.5000 1.0000 1.0000 0.5000 1.0000 1.5000 1.5000 0.5000 0 2.0000 2.0000 1.5000 1.5000 1.0000 2.5000 1.5000 2.0000 0.5000 0 2.5000 4.0000 1.5000 1.5000 1.5000 3.0000 2.0000 2.5000 0.5000 0.5000 2.5000 4.0000 2.0000 2.5000 1.5000 3.5000 3.0000 3.5000 0.5000 1.0000 3.0000 4.5000 2.5000 2.5000 1.5000 4.0000 3.0000 4.0000 1.5000 2.0000 3.5000 5.0000 2.5000 3.5000 3.0000 4.5000 3.5000 4.5000 2.5000 3.0000

Plus de réponses (1)

KSSV
KSSV le 18 Août 2022
Modifié(e) : KSSV le 18 Août 2022
% Make data for demo
A = cell(6,2) ;
for i = 1:6
for j = 1:2
A{i,j} = rand(1,10) ;
end
end
% Get mean
iwant = cellfun(@mean,A)
iwant = 6×2
0.4699 0.4161 0.6041 0.3679 0.5048 0.4849 0.3682 0.4060 0.4757 0.3761 0.3571 0.4127
Or you can also run loop.
  1 commentaire
Prashant Bhagat
Prashant Bhagat le 18 Août 2022
Actually, I didn't exlain my question very well. Actually I want to take average of elemnet of array. So
Z =
6×2 cell array
{[1 0 2 2 1 1 3 1 1 0]} {[2 1 0 0 0 1 0 2 0 0]}
{[2 2 3 3 1 3 3 2 1 0]} {[2 2 0 0 1 2 0 2 0 0]}
{[2 3 3 3 2 3 4 2 1 0]} {[3 5 0 0 1 3 0 3 0 1]}
{[2 3 3 5 2 3 6 3 1 1]} {[3 5 1 0 1 4 0 4 0 1]}
{[2 4 3 5 2 3 6 3 1 2]} {[4 5 2 0 1 5 0 5 2 2]}
{[2 5 3 7 3 4 6 3 1 3]} {[5 5 2 0 3 5 1 6 4 3]}
the result should be like { [ 1.5 0.5 1 1 0.5 1 1.5 1.5 0.5 0] } for the underlined part of the cell array. I want to do this for rest of the cell array.

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